Question

我需要使用jquery UI Datepicker计算两个日期之间的剩余天数，不包括Holidays和WeekDays（周六，周日）。

我已经成功计算了不包括工作日的剩余天数，但只是暂停了国家假期。如何在计算剩余天数时排除这些国定假日。

这是代码：

var natDays=[]; 
natDays[0]=[1, 27];
natDays[1]=[2, 6];
natDays[2]=[3, 17];
natDays[3]=[2, 7]; 
function nationalDays(date) {
    for (i = 0; i < natDays.length; i++) {
        if (date.getMonth() == natDays[i][0] - 1
            && date.getDate() == natDays[i][1]) {
            return [false, natDays[i][2] + '_day'];
        }
    }
    return [true, ''];
}
function noWeekendsOrHolidays(date) {
    var noWeekend = $.datepicker.noWeekends(date);
    if (noWeekend[0]) {
        return nationalDays(date);
    } else {
        return noWeekend;
    }
}
function excludeWeekDaysOrHolidays(startDate, endDate) {
    if (endDate < startDate){
        return 0;
    }
    // Calculate days between dates
    var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
    startDate.setHours(0,0,0,1);  // Start just after midnight
    endDate.setHours(23,59,59,999);  // End just before midnight
    var diff = endDate - startDate;  // Milliseconds between datetime objects    
    var days = Math.ceil(diff / millisecondsPerDay);
    // Subtract two weekend days for every week in between
    var weeks = Math.floor(days / 7);
    var days = days - (weeks * 2);
    // Handle special cases
    var startDay = startDate.getDay();
    var endDay = endDate.getDay();
    // Remove weekend not previously removed.   
    if (startDay - endDay > 1)         
    days = days - 2;      
    // Remove start day if span starts on Sunday but ends before Saturday
    if (startDay == 0 && endDay != 6)
        days = days - 1  
    // Remove end day if span ends on Saturday but starts after Sunday
    if (endDay == 6 && startDay != 0)
        days = days - 1  
    //check if National Holiday is in between two dates
    if (noWeekendsOrHolidays(date)[0]) {
        days=nationalDays(date);

    }   
    return days;
}

任何帮助将不胜感激！

另外，我正在尝试以下代码：

diff=endDate-startDate;
var holi=new Array("02-25-2013","05-22-2013","06-28-2013");
p=0;
hcnt=0;
while(p<holi.length)
{
    holiday=new Date(holi[p]);
    //alert(holiday);
    if(diff>holiday-startDate)
        hcnt++;
        //alert(hcnt);
        p++;
    }

假日返回“无效日期”错误。 hcnt始终显示为0.

Answer 1

试试这个：

new Date("YYYY-MM-DD");

而不是“MM-DD-YYYY”......

在你的情况下：

var holi = new Array("2013-02-25", "2013-05-22", "2013-06-28");

计算日期在两个日期之间离开，不包括jquery UI datepicker中的国家假日

1 个答案: