Question

我尝试从javascript使用IOS调用函数但仍然无法正常帮助我！

这个javascript

function geturl(getdata) {
   // document.getElementById('test1').src = '';
     alert(getdata);
}

和IOS代码

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {

    NSURL *URL = [inRequest URL];
    NSString *stringURL = [NSString stringWithFormat:@"%@",URL];
    NSString *urlString = inRequest.URL.absoluteString;

    NSString * getdata  = @"come please";
    NSString * sendBack = [NSString stringWithFormat:@"geturl('%@')",getdata];
    [subView stringByEvaluatingJavaScriptFromString:sendBack];// subView is UIWebview

  return YES;
}

我尝试使用这样但数据不警报我不知道发生了什么事请帮助我!!

  -(void)webViewDidFinishLoad:(UIWebView *)webView{

        if (loadingPage < [book count]) {

            NSURL *url = [NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:[book objectAtIndex:loadingPage] ofType:@"html" inDirectory:@""]];
            [[scrollView.subviews objectAtIndex:loadingPage] loadRequest:[NSURLRequest requestWithURL:url]];
            [[scrollView.subviews objectAtIndex:loadingPage] setHidden:NO];
            loadingPage++;
            subView.scrollView.bounces = NO;
            [[subView scrollView] setBounces: NO];       
        }
        NSString * getdata  = @"come please";
        NSString * sendBack = [NSString stringWithFormat:@"geturl('%@')",getdata];
        [subView stringByEvaluatingJavaScriptFromString:sendBack];


    }

我也试过这个，但仍然无法正常工作。如果我出错了，请告诉我

Answer 1

请确保subView是UIWebView对象，并且您需要在YES方法中返回NO或shouldStartLoadWithRequest。还有一个小解决方案 - 使用模拟器或设备打开safari调试器，并在控制台中手动检查此功能

带有IOS问题的UIWebView javascript

1 个答案: