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Question

我有这张桌子：

   ID       Name    01  02  03  04  05  06  07

0000068 Name1                       V   VX  

0000069 Name2       V   VX  VX      V       V

0000070 Name3           V   V   V   V   V   V

这是一个缺席检查表，我想计算从01到07列的每一行的数据量，所以我希望第一行将得到2，第二行5和第三行6的结果。如果可能，我希望将结果添加为新列。有办法以某种方式工作吗？

Answer 1

如果它总是V或VX，您可以将VX替换为V，连接他们在一起并采取LEN()：

SELECT *, LEN(REPLACE([01]+[02]+[03]+[04]+[05]+[06]+[07],'X','')) AS New_Ct
FROM YourTable

如果空白实际上是NULL，则必须将它们包裹在ISNULL()中：

SELECT *, LEN(REPLACE(ISNULL([01],'')+ISNULL([02],'')+ISNULL([03],'')+ISNULL([04],'')+ISNULL([05],'')+ISNULL([06],'')+ISNULL([07],''),'X','')) AS New_Ct
FROM Table1

演示：SQL Fiddle

Answer 2

SELECT 01 + 02 + 03 + 04 + 05 + 06 + 07 AS total_number FROM table_name;

Answer 3

尝试这样

SELECT  ID,Name,
(Case When[01] IS Null or [01] = '' then 0 else 1 end) +
(Case When[02] IS Null or [02] = '' then 0 else 1 end) +
(Case When[03] IS Null or [03] = '' then 0 else 1 end) +
(Case When[04] IS Null or [04] = '' then 0 else 1 end) +
(Case When[05] IS Null or [05] = '' then 0 else 1 end) +
(Case When[06] IS Null or [06] = '' then 0 else 1 end) +
(Case When[07] IS Null or [07] = '' then 0 else 1 end) AS Total
FROM table1;

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Answer 4

如果列数是静态的，则可以使用简单的CASE表达式。

SELECT *,
 CASE WHEN [01] = '' OR [01] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [02] = '' OR [02] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [03] = '' OR [03] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [04] = '' OR [04] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [05] = '' OR [05] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [06] = '' OR [06] IS NULL THEN 0 ELSE 1 END +
 CASE WHEN [07] = '' OR [07] IS NULL THEN 0 ELSE 1 END [cnt]
FROM Table1;

An SQLfiddle to test with

如何计算每行的数据量

4 个答案:

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