Question

我问过一个类似的问题，可以在这里找到：Python Login Script; Usernames and Passwords in a separate file

但是，我现在正在寻求扩展脚本，以便它可以查看文本文件中每个用户帐户的多个密码，并知道第一个密码是合法密码，而链接到该帐户的任何其他指定密码将抛出发出错误信息。

现在，外部用户名文件已设置为：

管理：AdminPW

现在我想扩展它以设置类似

的东西

管理员：AdminPW; adminpw; adminpw123;联系

如果输入最后4个密码，则会抛出特定的错误消息

我的代码是：

import getpass

credentials = {}                                                            ## Sets up an array for the login credentials
with open('Usernames.txt', 'r') as f:                                       ## Opens the file and reads it
    for line in f:  ## For each line
        username, password = line.strip().split(':')                        ## Separate each line into username and password, splitting after a colon
        credentials[username] = password                                    ## Links username to password

loop = 'true'
while (loop == 'true'):

    username = raw_input("Please enter your username: ")                    ## Asks for username

    if (username in credentials):                                           ## If the username is in the credentials array
        loop1 = 'true'
        while (loop1 == 'true'):
            password = getpass.getpass("Please enter your password: ")      ## Asks for password
            if (password == credentials[username]):                         ## If the password is linked to the username
                print "Logged in successfully as " + username               ## Log in
                loop = 'false'
                loop1 = 'false'
            else:
                print "Password incorrect!"

    else:
        print "Username incorrect!"

我尝试过使用“.strip（';'）”，但它没有用。我对Python仍然缺乏经验，所以我不确定下一步该怎么做

非常感谢任何帮助！

Answer 1

import getpass

credentials = {}                                                            ## Sets up an array for the login credentials
with open('Usernames.txt', 'r') as f:                                       ## Opens the file and reads it
    for line in f:  ## For each line
        username, delim, password = line.strip().partition(':')                        ## Separate each line into username and password, splitting after a colon
        credentials[username] = password.split(';')                                    ## Links username to password

while True:
    username = raw_input("Please enter your username: ")                    ## Asks for username
    if username in credentials:                                           ## If the username is in the credentials array
        while True:
            password = getpass.getpass("Please enter your password: ")      ## Asks for password
            if password == credentials[username][0]:
                print "Logged in successfully as " + username               ## Log in
                break
            elif password in credentials[username]:                         ## If the password is linked to the username
                print "Specific error message " + username               ## Log in
            else:
                print "Password incorrect!"
        break
    else:
        print "Username incorrect!"

如果您每次只要求新鲜的用户名/密码，那就更简单了。你拥有它的方式 - 如果用户错误地输入别人的用户名，他们将永远陷入循环，除非他们能猜出密码。

while True:
    username = raw_input("Please enter your username: ")                     
    password = getpass.getpass("Please enter your password: ")      
    if username in credentials and password == credentials[username][0]:
        print "Logged in successfully as " + username    
        break
    elif password in credentials.get(username, []):
        print "Specific error message " + username    
    else:
        print "Login incorrect!"

Answer 2

我有一个密码程序，我已经完成了GCSE课程的一部分。它是python 3.2.3但原理是一样的。您想加密密码。执行此操作的最佳方法（我认为）是哈希密码并将其保存在.txt文件中。示例...

file = open("pwdfile.txt", "a+")
pwd = getpass.getpass("Enter Password...").encode("utf-8")
pwd = hashlib.sha512(pwd).hexdigest()
file.write(pwd)
file.close()

现在您的密码已经完全加密，没有破解者会知道它是什么。 pwdfile.txt看起来像这样：＆＃34; 522e8eca613e7b41251ad995ba6406571f0b62a701e029c8e1eb24cb3b93f89a95c296aa91cde7dcb8da86fda66eda5432b206a7bc3e9b74f033d961da962e1b＆＃34;

现在读取密码，即。要登录，你需要输入用户密码，以相同的方式对其进行哈希处理，如果两者匹配，则将其登录。哈希的好处是，即使黑客掌握了pwdfile.txt，他们也可以＆＃t; t＆＃34;解码＆＃34;就这样。

要记录某人：

file = open("pwdfile.txt", "a+")
pwd = file.read()
userpwd = getpass.getpass("Enter password...").encode("utf-8")
userpwd = hashlib.sha512(pwd).hexdigest()
if userpwd == pwd:
   print("LOGIN")
else:
   print("ERROR")

希望这有帮助！：d

Answer 3

密码==凭证[用户名]我不明白你要用这条线做什么。凭证[username]将所有密码作为单个字符串返回。如果您正在尝试查找与输入的密码和要存储的值匹配的匹配项，请使用split（;）再次拆分并与每个结果进行比较。

Python登录脚本;每个帐户多个密码

3 个答案: