Question

我知道Admin SDK Directory API中的Users list endpoint。但是，它实际上很慢，因为您必须遍历所有用户来计算计数。

我也了解管理设置API中的currentNumberOfUsers endpoint。但是，该API没有只读范围，并且包含许多其他可能敏感的信息。

是否有用于检索域上当前帐户数的只读API？

Answer 1

如果您传递＆＃34;字段＆＃34;用户列表端点并不那么慢参数而不是请求所有用户数据。一个好的＆＃34;领域＆＃34;值可以是＆＃34; users / primaryEmail＆＃34;。

Answer 2

如果你只需要计数，你实际上可以只迭代userList

morsedict = {'A': '.-',
             'E': '.',
             'I': '..',
             'O': '---',
             'U': '..-'}


def countcombinations(codelist):
    # Generate the DP array to match the size of the codeword
    maxcombinations = [0] * (len(codelist))

    # How many unique strings can I create with access to j elements: j = current index
    # j = 0: access to nothing (1 because we need somewhere to start)
    maxcombinations[0] = 1

    # Brute force calculate the first case due to its simplicity
    if codelist[0: 2] in morsedict.values():
        maxcombinations[1] = 1
    else:
        maxcombinations[1] = 0

    # For the rest of the indices, we look back in the DP array to see how good we can do given a certain length string
    for i in range(1, len(codelist)):
        firststr = codelist[i]
        secondstr = codelist[(i - 1): i + 1]
        thirdstr = codelist[(i - 2): i + 1]

        if len(firststr) is 1 and firststr in morsedict.values():
            maxcombinations[i] += maxcombinations[i - 1]
        if len(secondstr) is 2 and secondstr in morsedict.values():
            maxcombinations[i] += maxcombinations[i - 2]
        if len(thirdstr) is 3 and thirdstr in morsedict.values():
            maxcombinations[i] += maxcombinations[i - 3]

    print(maxcombinations[-1])


if __name__ == "__main__":
    input()
    codelist = input()
    countcombinations(codelist)

Google Apps Marketplace应用程序如何检索特定域上的用户数量？

2 个答案: