我有一个看起来像这样的文本文件:
abcd nasj uasdy 3452 2314134
abcd efgh sdfdsf 234553 9323454
abcd asdf asdfasdf 34545 5234523
abcd sdfa sadfad 435232434 3452435
现在我正在尝试使用awk
计算第5列和第4列之间的比率,我尝试了这个:
BEGIN { printf "%10s %10s" "Column1:", "Ratio:%s" }
{ printf "%10s %10f" $1, ($6)/($5) }
但我不断收到错误说:
awk: awkRatio.awk:1: fatal: not enough arguments to satisfy format string
`%10s %10sColumn1:'
^ ran out for this one
答案 0 :(得分:3)
看起来你错过了printf "..."
之后的逗号
尝试:
BEGIN { printf "%10s %10s", "Column1:", "Ratio:" }
{ printf "%10s %10f", $1, ($5)/($4) }
答案 1 :(得分:1)
有人这样吗?
awk 'BEGIN { printf "%10s %10s","Column1:","Ratio:\n" } file
{ printf "%10s %10f\n" ,$1, ($5/$4) }'
Column1: Ratio:
abcd 670.374855
abcd 39.749882
abcd 151.527660
abcd 0.007932