Question

我需要遍历来自服务器的JSON数组。它看起来完全像这样：

[{"username":"betontester"},{"username":"kuesst"},{"username":"master_pat"},{"username":"olli"},{"username":"test15"},{"username":"test20140216"},{"username":"test789"},{"username":"tester100"},{"username":"tobi"}]

我在这里找到了一些建议，但它们似乎都不适合我。有没有简单的方法可以获得所有这些价值？

Answer 1

 var arr = [{"username":"betontester"},{"username":"kuesst"},{"username":"master_pat"},{"username":"olli"},{"username":"test15"},{"username":"test20140216"},{"username":"test789"},{"username":"tester100"},{"username":"tobi"}];

    for(var i = 0; l = arr.length; i< l; i+=1)
    {
    console.log(arr[i].username); // log username
    }

另一种选择：

arr.forEach(function(i) {
    console.log(i.username)
});

Answer 2

var data = [{"username":"betontester"},{"username":"kuesst"},{"username":"master_pat"},{"username":"olli"},{"username":"test15"},{"username":"test20140216"},{"username":"test789"},{"username":"tester100"},{"username":"tobi"}],
    usernames = [];

for(var i=0; i<data.length; i++) {
    usernames.push(data[i].username);
}

Answer 3

试试这个：

var o = [{"username":"betontester"},{"username":"kuesst"},{"username":"master_pat"},{"username":"olli"},{"username":"test15"},{"username":"test20140216"},{"username":"test789"},{"username":"tester100"},{"username":"tobi"}];
for(var i = 0; i < o.length ; i++) 
    for(var j in o[i]) 
        alert(j + ": " + o[i][j]);

Answer 4

如果您不需要IE＆lt; 9兼容性，则可以使用Array.prototype.map()

var arr = [{"username":"betontester"},{"username":"kuesst"},{"username":"master_pat"},{"username":"olli"},{"username":"test15"},{"username":"test20140216"},{"username":"test789"},{"username":"tester100"},{"username":"tobi"}],
    usernames = arr.map(function(item) {
        return item.username;
    });

在JavaScript或jQuery中迭代JSON数组

4 个答案: