Question

下面的代码将回显yes，no，may或来自db的文本。我希望输出在这样的表中

echo "<tr><td><b>OUTPUT HERE</b></td></tr>";

这是完整的代码。

<?php
global $wpdb;
$current_user = wp_get_current_user();
$result = $wpdb->get_results( "
SELECT stats.*
  FROM wp_wp_pro_quiz_statistic stats
       JOIN wp_wp_pro_quiz_statistic_ref refs on stats.statistic_ref_id = refs.statistic_ref_id
WHERE refs.user_id= $current_user->ID  && refs.quiz_id= 5");
foreach($result as $row) {
echo "<tr><td><b></b></td></tr>";
$a = $row->answer_data;
$b = json_decode($a, true);
if($b[0] == 1){ echo 'Yes'; }
if($b[1] == 1){ echo 'No'; }
if($b[2] == 1){ echo 'Maybe'; }
if(count($b) == 1){ echo '$row->answer_data'; }
}
?>

我希望有人可以帮助并感谢你

Answer 1

您可以回显开始标记，然后是内容，关闭它们。

<?php
echo "<tr><td><b>";
// Echo query results 
echo "</b></td></tr>";

Answer 2

你可以这样做：

foreach($result as $row) {
 if(count($b) == 1){//maybe > 0 ?
  echo "<tr><td><b>";
  $a = $row->answer_data;
  $b = json_decode($a, true);
  if($b[0] == 1){ echo 'Yes'; }
  if($b[1] == 1){ echo 'No'; }
  if($b[2] == 1){ echo 'Maybe'; }
  echo $row->answer_data;
  echo "</b></td></tr>";
 }

}

Answer 3

试试这个：它会起作用。

 <?php
    global $wpdb;
    $current_user = wp_get_current_user();
    $result = $wpdb->get_results( "
    SELECT stats.* FROM wp_wp_pro_quiz_statistic stats JOIN wp_wp_pro_quiz_statistic_ref refs on stats.statistic_ref_id = refs.statistic_ref_id WHERE refs.user_id= $current_user->ID  && refs.quiz_id= 5");

    foreach($result as $row) {   
     $a = $row->answer_data;
     $b = json_decode($a, true);
     $myOutput;
     if($b[0] == 1){ $myOutput = 'Yes'; }
     if($b[1] == 1){ $myOutput = 'No'; }
     if($b[2] == 1){ $myOutput = 'Maybe'; }
     if(count($b) == 1){ 
       echo "<tr><td><b>".$myOutput."</b></td></tr>";
     }
    }
 ?>

将数据输出到表中

3 个答案: