使用XPath从XBRL中提取数据

Question

我正在尝试使用Talend Studio中的XPath表达式从XBRL文件中提取一些数据点。我想提取所有ShareHolderFunds值和它所涉及的时间段的结束日期（由“ContextRef”属性引用），以及公司注册的号码。我正在努力建立到期末日期的链接 - 目前我的代码错误地返回了两个ShareHolderFund值的相同结束日期。

以下是我的代码Talend Studio的屏幕截图：

这是XBRL的摘录：

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="http://www.companieshouse.gov.uk/ef/xbrl/uk/fr/gaap/ae/2009-06-21/stylesheet/CH-AE-stylesheet.xsl"?>
<xbrl xmlns="http://www.xbrl.org/2003/instance" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ae="http://www.companieshouse.gov.uk/ef/xbrl/uk/fr/gaap/ae/2009-06-21" xmlns:gc="http://www.xbrl.org/uk/fr/gcd/2004-12-01" xmlns:html="http://www.w3.org/1999/xhtml" xmlns:iso4217="http://www.xbrl.org/2003/iso4217" xmlns:link="http://www.xbrl.org/2003/linkbase" xmlns:pt="http://www.xbrl.org/uk/fr/gaap/pt/2004-12-01" xmlns:xbrli="http://www.xbrl.org/2003/instance" xmlns:xlink="http://www.w3.org/1999/xlink">
<link:schemaRef xlink:arcrole="http://www.w3.org/1999/xlink/properties/linkbase" xlink:href="http://www.companieshouse.gov.uk/ef/xbrl/uk/fr/gaap/ae/2009-06-21/uk-gaap-ae-2009-06-21.xsd" xlink:type="simple" />
<ae:CompanyNotDormant contextRef="y2013">true</ae:CompanyNotDormant>
<gc:EntityNames>
  <gc:EntityCurrentLegalName contextRef="y2013">A &amp; Co. Limited</gc:EntityCurrentLegalName>
</gc:EntityNames>
<ae:CompanyIdentifyingNumbers>
  <ae:CompaniesHouseRegisteredNumber contextRef="y2013">123456</ae:CompaniesHouseRegisteredNumber>
</ae:CompanyIdentifyingNumbers>
<gc:StatementDatesPeriodsCovered>
  <gc:BalanceSheetDate contextRef="e2013">2013-03-31</gc:BalanceSheetDate>
</gc:StatementDatesPeriodsCovered>

<pt:ShareholderFunds precision="5" contextRef="e2013" unitRef="GBP">5286</pt:ShareholderFunds>
<pt:ShareholderFunds precision="5" contextRef="e2012" unitRef="GBP">5446</pt:ShareholderFunds>

<unit id="shares">
  <measure>xbrli:shares</measure>
</unit>
<unit id="GBP">
  <measure>iso4217:GBP</measure>
</unit>
<unit id="pure">
  <measure>xbrli:pure</measure>
</unit>

<context id="e2012">
  <entity>
    <identifier scheme="Ellco/results">A &amp; Co. Limited</identifier>
  </entity>
  <period>
    <instant>2012-03-31</instant>
  </period>
</context>
<context id="s2013">
  <entity>
    <identifier scheme="Ellco/results">A &amp; Co. Limited</identifier>
  </entity>
  <period>
    <instant>2012-03-31</instant>
  </period>
</context>
<context id="e2013">
  <entity>
    <identifier scheme="Ellco/results">A &amp; Co. Limited</identifier>
  </entity>
  <period>
    <instant>2013-03-31</instant>
  </period>
</context>
<ae:CompaniesHouseDocumentAuthentication contextRef="y2013"> </ae:CompaniesHouseDocumentAuthentication>
<ae:DateAccountsReceived contextRef="e2013">2013-12-25</ae:DateAccountsReceived>
</xbrl>

Answer 1

使用XPath，我可以使用以下代码选择两个不同的日期：

/xbrl/context[@id = /xbrl/pt:ShareholderFunds/@contextRef]/period/instant

该表达式选择xbrl/context元素，其id属性与/xbrl/pt:ShareholderFunds contextRef属性相对应，并在每个元素中获取period/instant。选择的结果是包含以下内容的节点集：

2012-03-31
2013-03-31