Question

所以我试图找出如何获取我的PHP查询并在网格视图中显示它们。我想让它成为一个3列的网格，所以它看起来像这样：第一列：1,2,3第二列：4,5,6等等......

以下是我通过PHP查看MySQL查询的代码：

<div class='main_col'> <!--Start of the Main-->
<div class='main_content'>
<?php
include("includes/connect.php");

$select_games = "SELECT * FROM games";

$run_games = mysql_query($select_games);

while($row = mysql_fetch_array($run_games)){

$game_id = $row['game_id'];
$game_name = $row['game_name'];
$game_category = $row['game_name'];
$game_keywords = $row['game_name'];
$game_image = $row['game_image'];

?>

<p><a href="game_page.php?id=<?php echo $game_id; ?>"><?php echo $game_name; ?></a></p>

<a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php echo $game_image; ?>" width="120" /></a>

<?php } ?>
</div>
</div> <!--End of the Main-->

我试过了：

<div class='main_col'> <!--Start of the Main-->
<div class='main_content'>
<?php
include("includes/connect.php");

$select_games = "SELECT * FROM games";

$run_games = mysql_query($select_games);

while($row = mysql_fetch_array($run_games)){

$game_id = $row['game_id'];
$game_name = $row['game_name'];
$game_category = $row['game_name'];
$game_keywords = $row['game_name'];
$game_image = $row['game_image'];

?>

<table>

<tr>
<td><p><a href="game_page.php?id=<?php echo $game_id; ?>"><?php echo $game_name; ?></a></p>

<a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php      echo $game_image; ?>" width="120" /></a></td>
</tr>
</table>
<?php } ?>
</div>
</div> <!--End of the Main-->

建议任何人？：（

Answer 1

首先，你应该真的不再使用不赞成的 mysql扩展。相反，您应该使用MySQLi或PDO。

接下来，你想要一个包含3列的表。每个数据字段应包含3个游戏。所以这意味着在每3场比赛之后，你想要在每9场比赛之后进行比赛，开始一个新的比赛。您可以使用模运算符（％）来查看何时有3（或6或9等）游戏，以及何时有9/18/27 /等。游戏，像这样：

<div class='main_col'> <!--Start of the Main-->
<div class='main_content'>
<?php
include("includes/connect.php");

$run_games = mysql_query("SELECT * FROM games");

echo '<table>';
$games = 0;
while($row = mysql_fetch_array($run_games)){
   // make a new row after 9 games
   if($games%9 == 0) {
      if($games > 0) {
         // and close the previous row only if it's not the first
         echo '</tr>';
      }
      echo '<tr>';
   }
   // make a new column after 3 games
   if($games%3 == 0) {
      if($games > 0) {
         // and only close it if it's not the first game
         echo '</td>';
      }
      echo '<td>';
   }

   $game_id = $row['game_id'];
   $game_name = $row['game_name'];
   $game_category = $row['game_name'];
   $game_keywords = $row['game_name'];
   $game_image = $row['game_image'];
   ?>

   <a href="game_page.php?id=<?php echo $game_id; ?>"><?php echo $game_name; ?></a><br />
   <a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php echo $game_image; ?>" width="120" /></a>
   <?php 
   $games++; // increment the $games element so we know how many games we've already processed
}
?>
</table>
</div>
</div> <!--End of the Main-->

或者，如果你只是想要每场1场比赛，你可以使用这样的东西：

<div class='main_col'> <!--Start of the Main-->
<div class='main_content'>
<?php
include("includes/connect.php");

$run_games = mysql_query("SELECT * FROM games");

echo '<table>';
$games = 0;
while($row = mysql_fetch_array($run_games)){
   // make a new row after 3 games
   if($games%3 == 0) {
      if($games > 0) {
         // and only close it if it's not the first game
         echo '</tr>';
      }
      echo '<tr>';
   }

   $game_id = $row['game_id'];
   $game_name = $row['game_name'];
   $game_category = $row['game_name'];
   $game_keywords = $row['game_name'];
   $game_image = $row['game_image'];
   ?>
   <td>
   <a href="game_page.php?id=<?php echo $game_id; ?>"><?php echo $game_name; ?></a><br />
   <a href="game_page.php?id=<?php echo $game_id; ?>"><img src="images/games_images/<?php echo $game_image; ?>" width="120" /></a>
   </td>
   <?php 
   $games++; // increment the $games element so we know how many games we've already processed
}
?>
</table>
</div>
</div> <!--End of the Main-->

为PHP查询创建网格视图

1 个答案: