Question

我想我会对简单的事情发疯。

以下代码：

        NSLog(@"potentialPositions: %@, with count: %i", potentialPositions, [potentialPositions count]);

    for (NSUInteger i = 1; i < (choices); i++) {
        NSLog(@"i = %i",i);
        [self drawAWord:[[currentLevel objectAtIndex:levelLink] objectAtIndex:i] atPoint:[[potentialPositions objectAtIndex:i] CGPointValue] withInitialZoom:FALSE];
    }

产生以下结果：

2014-02-15 20:31:54.329 ThesaurusLinks[12446:70b] potentialPositions: (
"NSPoint: {180, 125}",
"NSPoint: {270, 200}",
"NSPoint: {350, 250}",
"NSPoint: {280, 160}"
), with count: 4
2014-02-15 20:31:54.330 ThesaurusLinks[12446:70b] i = 1
2014-02-15 20:31:54.331 ThesaurusLinks[12446:70b] i = 2
2014-02-15 20:31:54.331 ThesaurusLinks[12446:70b] i = 3
2014-02-15 20:31:54.334 ThesaurusLinks[12446:70b] *** Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[__NSArrayM objectAtIndex:]: index 3 beyond bounds [0 .. 2]'

数组中显然有四个名为“potentialPositions”的对象。为什么它认为边界只有0..2？它不能在我的DrawAWord方法中，因为我放了一个NSLOG（结果未在上面显示）它不会被调用i = 3.我很难过。

感谢您的任何答案或提示。

Answer 1

什么

[currentLevel objectAtIndex:levelLink]

返回？似乎问题在这里。添加

NSLog(@"%@",[currentLevel objectAtIndex:levelLink]);

查看它有多少元素。

Answer 2

你想从0开始：

for (NSUInteger i = 0; i < (choices); i++)

NSArray指数超出界限

2 个答案: