Question

我正在尝试创建一个返回包含四个值的表的UDF：

CREATE TABLE ts_table
(
  id character varying, 
  year integer, 
  rank double precision, 
  votes integer
);

然后，使用UDF，我必须返回一个由（某些东西）定义的表：

CREATE FUNCTION ts_myfunc(text) RETURNS SETOF ts_table AS $$
    'SELECT id,year,rank,votes FROM productions NATURAL JOIN directors NATURAL JOIN ratings WHERE attr is NULL AND pid=$1 ORDER BY year;'
$$ LANGUAGE SQL;

但是，当我尝试使用该命令创建UDF时，我得到了

ERROR:  syntax error at or near "'SELECT id,year,rank,votes FROM productions NATURAL JOIN directors NATURAL JOIN ratings WHERE attr is NULL AND pid=$1 ORDER BY year;'"
LINE 2: 'SELECT id,year,rank,votes FROM productions NATURAL JOIN dir...

Answer 1

更改线路 'SELECT id,year,rank,votes FROM productions NATURAL JOIN directors NATURAL JOIN ratings WHERE attr is NULL AND pid=$1 ORDER BY year;'

到

SELECT id,year,rank,votes FROM productions NATURAL JOIN directors NATURAL JOIN ratings WHERE attr is NULL AND pid=$1 ORDER BY year;

（删除单引号）将解决问题。

用户定义函数返回PostgreSQL中的表

1 个答案: