Question

我写了这段代码来从instagram下载图片。下载的图像，但它有一些错误。这意味着我可以下载图像，但我无法打开它

<?php
  $linktopage = 'http://instagram.com/p/jTh1cBHG36/';

  $sourcecode = file_get_contents( $linktopage );

  $sourcecode = substr($sourcecode , strpos($sourcecode, 'og:image') + 19, strlen($sourcecode)); 
  $sourcecode = substr($sourcecode , 0 , strpos($sourcecode, '"'));
  $name= substr($sourcecode , strpos($sourcecode, 'com/') + 4, strlen($sourcecode));


  $fileToSend = $sourcecode;

  header('Content-type: image/jpeg');
  header('Content-Disposition: attachment; filename='.$name.'"');
  header("Content-Length: ". file_size($fileToSend));

  readfile($fileToSend);

?>

Answer 1

评论Content-Length行，它会正常工作：

//header("Content-Length: ". file_size($fileToSend));

正确的函数名称为filesize（我不确定它是否适用于您的网址）。

我也发现你在filename=之后错过了一个引用。它应该是：

header('Content-Disposition: attachment; filename="'.$name.'"');

因此，您的代码的工作版本将是：

  $linktopage = 'http://instagram.com/p/jTh1cBHG36/';

  $sourcecode = file_get_contents( $linktopage );

  $sourcecode = substr($sourcecode , strpos($sourcecode, 'og:image') + 19, strlen($sourcecode)); 
  $sourcecode = substr($sourcecode , 0 , strpos($sourcecode, '"'));
  $name= substr($sourcecode , strpos($sourcecode, 'com/') + 4, strlen($sourcecode));


  $fileToSend = $sourcecode;

  header('Content-type: image/jpeg');
  header('Content-Disposition: attachment; filename="'.$name.'"');
  //header("Content-Length: ". filesize($fileToSend));

  readfile($fileToSend);

Answer 2

由于拼写错误，问题正在发生。

错字错误发生在以下行：

header('Content-Disposition: attachment; filename='.$name.'"');

由于名称格式错误＆＃39; _＆＃39;被添加到文件扩展名。

代码中的另外一个内容是内容长度，仅为2行：

$head = array_change_key_case(get_headers($sourcecode, TRUE));
$filesize = $head['content-length'];

修正了拼写错误的最终工作代码：

<?php
    $linktopage = 'http://instagram.com/p/jTh1cBHG36/';
    $sourcecode = file_get_contents( $linktopage );
    $sourcecode = substr($sourcecode , strpos($sourcecode, 'og:image') + 19, strlen($sourcecode)); 
    $sourcecode = substr($sourcecode , 0 , strpos($sourcecode, '"'));
    $name= substr($sourcecode , strpos($sourcecode, 'com/') + 4, strlen($sourcecode));
    $fileToSend = $sourcecode;

    $head = array_change_key_case(get_headers($sourcecode, TRUE));
    $filesize = $head['content-length'];

    header("Content-type: image/jpeg");
    header("Content-Disposition: attachment; filename=".$name);
    header("Content-Length: ". $filesize);

    readfile($fileToSend);
?>

使用php脚本下载图像时出错

2 个答案: