Question

我正在创建一个测验活动，当用户将他或她的答案输入EditText并按下“下一步”按钮时，它将生成下一个随机单词并检查您是对还是错。

但是，出于某种原因，即使我的代码能够同时检测到EditText和正确的单词答案，它也会向我返回“错误答案”代码。有人可以帮我吗？谢谢！（我现在还是新人......）

* 编辑：这是不是重复的问题人。我真的需要有人专门查看我的代码并告诉我到底出了什么问题，因为我不知道。通过查看其他人的问题，这不是一个可以解决的问题（对我来说无论如何），因为我还是很陌生。非常感谢。*

btnNext.setOnClickListener(new OnClickListener(){


        @Override
        public void onClick(View v) {
            EditText etGuess= (EditText) findViewById(R.id.editTextGuess); 
            etguess2 = etGuess.getText().toString(); 
            //these two above were actually placed outside but no luck. didnt work here either

            String etg2str = etguess2; // the users edittext input
            String tgstr = theguess; // the correct answer, the guess is from outside

            if (myCD > 0 && etg2str.toString() == tgstr.toString()){

            myCD--; //this is a countdown of the number of qns
            Toast.makeText(getApplicationContext(), "correct answer"+ myCD + rantitle + " now",
                       Toast.LENGTH_LONG).show(); // this has nvr appeared for me
            savePreferences("countDown", myCD);
            RandomTitle(); //calling for random word on next load
            Intent iNext = new Intent(QuizActivity.this, 
                    QuizActivity.class);
            iNext.putExtra("dataR", rantitle); //inputting random word for next load
            startActivityForResult(iNext, 1);
            finish();
            }

            else if (myCD > 0 &&  etg2str.toString() != tgstr.toString()){

                myCD--;
                Toast.makeText(getApplicationContext(), "wrong answer " + myCD + rantitle + etguess2 + theguess + " now",
                           Toast.LENGTH_LONG).show();
            //now this one above appears for me everytime yet even tho etguess2 and theguess appears the same, I get wrong number


                savePreferences("countDown", myCD);
                RandomTitle();
                Intent iNext = new Intent(QuizActivity.this, 
                        QuizActivity.class);
                iNext.putExtra("dataR", rantitle);
                startActivityForResult(iNext, 1);
                finish();

            }

            else{

                Intent iScore = new Intent(QuizActivity.this, 
                        ScoreActivity.class);
                startActivityForResult(iScore, 1);
                myCD = 10;
                savePreferences("countDown", myCD);
            finish();

            }
        }


        });         
    }

Answer 1

你需要使用.equals（）来比较字符串：

etg2str.toString().equals(tgstr.toString());

==运算符用于比较基本类型，例如int

因此，对于您的不平等情况，您可以使用！操作者：

!etg2str.toString().equals(tgstr.toString());

字符串比较不起作用

1 个答案: