Question

在我的视图页面上，我通过ajax请求，在控制器操作上将一些值传递给控制器，在检查后，将消息值重定向到视图的控制器。将消息添加到模型和pasisng模型以再次使用新模型值查看。第二个时间（回发）模型值作为Json传递给视图，但新模型值（即消息）不能被javascript捕获。在我的代码中它是Model.INFO

        $.ajax({
            type: "POST",
            url: '@Url.Action("TeamSaveChanges", "Administrator")',
            data: {
                ID: '@Model.ID',
                doctorID: doctorValue,
                nurseID:nurseValue,
                driverID:driverValue,
                technicianID: technicianValue

            },
            dataType: "text",
            success: function () { alert("@Model.INFO")},
           error: function () { alert("Error occured!!!") }
        });

控制器

 public ActionResult TeamSaveChanges(Guid ID, Guid? doctorID, Guid? nurseID, Guid? driverID, Guid? technicianID)
    {
        try
        {

            using (var client = SoapProxyFactory.CreateDSrvGDSoapClient())
            {
                var emptyTeam = Guid.Empty;
                var ambID = client.getAmbulanceIDbyTeamID(ID);
                var baseresult = client.checkAmblanceTeamsforDuplicateMembers(ambID, ID);


                if (doctorID == emptyTeam && nurseID == emptyTeam &&   driverID == emptyTeam  && technicianID == emptyTeam  )
                {
                    var result = client.EditTeamMembers(ID, doctorID, nurseID, driverID, technicianID);
                    if (result)
                        throw new Exception("saved");
                }
                else 
                {
                    foreach (var item in baseresult)
                {
                        if(item.DOCTORCODE == doctorID && item.NURSECODE == nurseID &&  item.DRIVERCODE == driverID && item.TECHNICIANCODE == technicianID)
                            throw new Exception("The team with Same Members is exist." + "<p>(" + item.TEAMCODE + ")</p>");
                    }

                    var result = client.EditTeamMembers(ID, doctorID, nurseID, driverID, technicianID);
                    if (result)
                        throw new Exception("saved");
                }       
                  catch (Exception exp)
        {
            string message = exp.Message;
            return RedirectToAction("TeamMembers", "Administrator", new { ID = ID, message = message });


        }

   [OutputCache(Location = System.Web.UI.OutputCacheLocation.None)]
    public ActionResult TeamMembers(Guid? ID,string message)
    {
        try
        {
            if (!ID.HasValue())
               return RedirectToAction("Ambulance");


            using (var client = SoapProxyFactory.CreateDSrvALLSoapClient())
            {
               Guid id  = ID.Value;

                var clientGD = SoapProxyFactory.CreateDSrvGDSoapClient();
               var result = client.GetTeamMembers(id);
               result.INFO = message;
                if (message != null)
               {
                   result.INFO = message;
                   return  Json(result,JsonRequestBehavior.AllowGet);
               }

             return View(result);
            }

        }

Answer 1

这一行：

success: function () { alert("@Model.INFO")},

只会将模型的INFO拉入一次，因为它会在客户端中呈现服务器值。如果您希望它发生变化，那么您必须将结果传递回成功，并接受新值：

success: function (d) { alert(d); },

要向其返回值，您必须从操作返回：

return Content("SOMEVAL"); // or PartialView or something that is string data

但是，重定向到操作不会返回对调用者的响应，并且可能无法通过AJAX正确处理，所以我不能100％确定问题是什么......

Answer 2

为什么要使用AJAX呢？发生了什么事情是你的脚本向你的控制器发出一个请求，它将响应作为数据发回，而不是重定向到新的网页。

只需创建一个表单，以典型的MVC方式将这些变量POST到您的控制器，您将获得所需的结果。

MVC- ajax请求页面无法刷新

2 个答案: