Question

我从我的cookie中获取了这个字符串（例子）：

Cookies = "link1=whatever; link2=whatever; delete1=true; link3=whatever; delete3=true; link4=whatever;"

我想删除以delete开头的字符串的最后一部分，以“;”结尾或“”（没什么，刺痛结束）。在这个例子中，我想要 - ＆gt; delete3 = TRUE; ＆lt; - 要删除的部分

如何做到这一点？

Answer 1

你可以这样做：

Cookies = Cookies.split(';');
var i = Cookies.length,
    r = /^ *delete\d+=/;
while (--i >= 0) {
    if (r.test(Cookies[i])) {
        Cookies.splice(i, 1);
        Cookies = Cookies.join(';');
        break;
    } 
}

更短的方式：

Cookies = Cookies.replace(
    /; *delete\d+=[^;]*(?!.*; *delete\d+=)/, ''
);

更简单（基于Goran.it's answer）：

Cookies = Cookies.replace(/(.*;) *delete\d+=.*?;/, '$1');

随时询问详情。

Answer 2

这是一个简单的正则表达式解决方案：

var Cookies = "link1=whatever; link2=whatever; delete1=true; link3=whatever; delete3=true; link4=whatever;";
var fixed = Cookies.replace(/(.*)(\s?delete.*?;)(.*)$/, '$1$3');

// fixed is now: "link1=whatever; link2=whatever; delete1=true; link3=whatever;  link4=whatever;"

Answer 3

使用Javascript：

Cookies = "link1=whatever; link2=whatever; delete1=true; link3=whatever; delete3=true; link4=whatever;";

aa = Cookies.split(';');

for (_i = 0, _len = aa.length; _i < _len; _i++) {
  a = aa[_i];
  if (a.trim().search(/^delete/) !== -1) deleters = aa.indexOf(a);
}

aa.splice(deleters, 1);

Cookies = aa.join(';');

CoffeeScript的：

Cookies = "link1=whatever; link2=whatever; delete1=true; link3=whatever; delete3=true; link4=whatever;"
aa=Cookies.split(';')
for a in aa
    deleters=aa.indexOf(a) if a.trim().search(/^delete/)!=-1
aa.splice(deleters, 1)
Cookies = aa.join(';')

javascript如何删除字符串的某个部分？

3 个答案: