我在我的servlet中获得了ping结果。我正在尝试将其重定向到另一个jsp文件。
输出的jsp文件打开。但是没有显示。
这是我的servlet主代码
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String ip = request.getParameter("ip");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
// out.println("The ip address is:"+ip+"\n");
String result = pingTest(ip);
out.println(result);
String redirect = "Output.jsp";
RequestDispatcher view = request.getRequestDispatcher(redirect);//Is it good approach to redirect request in ajax based servlet?
view.forward(request, response);
}
这是我的output.jsp页面
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Ping Check Result</title>
</head>
<body>
</body>
</html
我是否需要在output.jsp中添加任何内容?
答案 0 :(得分:1)
在你的servlet中:
request.setAttribute("result", result);
request.getRequestDispatcher("/WEB-INF/Output.jsp").forward(request, response);
在你的JSP中:
<pre>The data from servlet: ${result}</pre>
答案 1 :(得分:0)
你的servlet必须是:
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String ip = request.getParameter("ip");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("The ip address is:"+ip+"\n");
String result = pingTest(ip);
out.println(result);
RequestDispatcher view = request.getRequestDispatcher();
view.forward(request, response);
}