Question

这是我想要插入应从另一个表中选择的值的查询：

insert into payment_details_kohin(installment_no)
 values(
select count(installment_amount)+2  
from kohin_plan.payment_details_insert 
where customer_id='KBP100058'
)

...但它给了我一个错误：

消息515，级别16，状态2，行1无法将值NULL插入列'customer_id'，表格 'kohinoor_rdfd.kohin_plan.payment_details_kohin';专栏没有允许空值。 INSERT失败。声明已经终止。

当我尝试以下查询时：

insert into payment_details_kohin(installment_no)
values(
select count(installment_amount)+2  
from kohin_plan.payment_details_insert 
where customer_id='KBP100058'
)

...它给了我以下错误

Msg 156, Level 15, State 1, Line 2
Incorrect syntax near the keyword 'select'.
Msg 102, Level 15, State 1, Line 3
Incorrect syntax near ')'.

Answer 1

您不需要这里的Values子句，只需执行以下操作

INSERT INTO payment_details_kohin(installment_no)
SELECT ISNULL(COUNT(installment_amount), 0) + 2  
FROM kohin_plan.payment_details_insert 
WHERE customer_id = 'KBP100058'

Answer 2

您的问题是您拥有非NULL客户ID。您还需要将其插入表中：

insert into payment_details_kohin(customer_id, installment_no)
    select customer_id, count(installment_amount)+2  
    from kohin_plan.payment_details_insert 
    where customer_id='KBP100058';

然而，当我看到inserts时，有时真正需要的是更新：

update payment_details_kohin
    set installment_no = (select count(installment_amount) + 2
                          from kohin_plan.payment_details_insert 
                          where payment_details_kohin.customer_id = payment_details_insert.customer_id
                         )
    where customer_id = 'KBP100058';

Answer 3

亲爱的朋友，当您从另一个表中的一个表中插入值或使用select for inseting时，您不必空间“值”关键字

如此简单，请执行以下操作

INSERT INTO payment_details_kohin(installment_no)
SELECT count(installment_amount) + 2  
FROM kohin_plan.payment_details_insert 
WHERE customer_id = 'KBP100058'

插入和选择组合不起作用

3 个答案: