我知道如何在进程崩溃时在OS X上生成核心转储,但我真正需要做的是附加到进程,生成核心转储,然后恢复该进程(不会杀死它)。
很久以前(也许一年半前)我有C代码可以做到这一点......它使用OS X内核库连接到进程,读取其所有线程状态和内存,以及将其写入磁盘上的Mach-O文件。这很好用(这正是我正在寻找的),但现在我似乎无法找到我的生活代码。我似乎记得代码与OS X系统内部书籍有些相关,但这只是一个模糊的回忆。
有谁知道我正在谈论的代码并且可以指出我的代码?如果没有,最好是通过一些示例代码知道一个好方法吗?
编辑:这是答案。
信息:http://osxbook.com/book/bonus/chapter8/core/
将为您完成的计划:http://osxbook.com/book/bonus/chapter8/core/download/gcore-1.3.tar.gz
答案 0 :(得分:6)
我相信您正在寻找this information
具体做法是:
/* UNIX Third Edition, circa early 1973 */
/* ken/sig.c */
core()
{
int s, *ip;
extern schar;
/* u is the user area */
u.u_error = 0; /* reset error code to "no error" */
u.u_dirp = "core"; /* file name to search for */
ip = namei(&schar, 1); /* do search; schar means it's a kernel string */
if (ip == NULL) { /* failed to find */
if (u.u_error) /* because of some error */
return(0); /* so bail out */
ip = maknode(0666); /* didn't exist; so create it */
}
if (!access(ip, IWRITE)) { /* check "write" permission; 0 means OK */
itrunc(ip); /* truncate the core file */
/* first we write the user area */
u.u_offset[0] = 0; /* offset for I/O */
u.u_offset[1] = 0; /* offset for I/O */
u.u_base = &u; /* base address for I/O (user area itself) */
u.u_count = USIZE*64; /* bytes remaining for I/O; USIZE=8 */
u.u_segflg = 1; /* specify kernel address space */
writei(ip); /* do the write */
/*
* u_procp points to the process structure
* p_size is the size of the process's swappable image (x 64 bytes) */
*/
s = u.u_procp->p_size - USIZE; /* compute size left to write */
/*
* This sets up software prototype segmentation registers to implement
* text(=0 here), data(=s here), and stack(=0 here) sizes specified.
*/
estabur(0, s, 0);
u.u_base = 0; /* base address for I/O (start of space) */
u.u_count = s*64; /* s is in units of 64 bytes, so adjust */
u.u_segflg = 0; /* specify user address space */
writei(ip); /* do the write */
}
iput(ip); /* decrement inode reference count */
return(u.u_error==0); /* done */
}