我有NSArray
NSDictionaries
,在NSDictionary
我有一个名为'rowID'的元素,保存为NSString
,但保存在其中的所有内容都是一个数字..但仍然是一个字符串值。
我想知道如何根据这个值对数组进行排序,但是在排序1-100方面,目前当我对它进行排序时,首先是10.当它应该是1-10时。
这就是我的排序方式:
NSArray *tempSortedItemsArray = [itemArray sortedArrayUsingDescriptors:
@[[NSSortDescriptor
sortDescriptorWithKey:@"rowID" ascending:YES]]];
答案 0 :(得分:6)
试试这个: -
NSArray *aSortedArray = [itemArray sortedArrayUsingComparator:^(NSMutableDictionary *obj1,NSMutableDictionary *obj2) {
NSString *num1 =[obj1 objectForKey:@"rowID"];
NSString *num2 =[obj2 objectForKey:@"rowID"];
return (NSComparisonResult) [num1 compare:num2 options:(NSNumericSearch)];
}];
答案 1 :(得分:2)
您可以按照以下代码进行数字排序: -
NSMutableArray *tmpAr = [[NSMutableArray alloc] init];
NSMutableDictionary *tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number5"];
[tmpDict setObject:@"5" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number3"];
[tmpDict setObject:@"3" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number2"];
[tmpDict setObject:@"2" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number1"];
[tmpDict setObject:@"1" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number4"];
[tmpDict setObject:@"4" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number25"];
[tmpDict setObject:@"25" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number10"];
[tmpDict setObject:@"10" forKey:@"id"];
[tmpAr addObject:tmpDict];
tmpDict = [[NSMutableDictionary alloc] init];
[tmpDict setObject:@"name" forKey:@"number7"];
[tmpDict setObject:@"7" forKey:@"id"];
[tmpAr addObject:tmpDict];
NSLog(@"tmpar1 = %@",tmpAr);
[tmpAr sortUsingComparator:
^(id obj1, id obj2)
{
NSInteger value1 = [[obj1 objectForKey: @"id"] intValue];
NSInteger value2 = [[obj2 objectForKey: @"id"] intValue];
if (value1 > value2)
{
return (NSComparisonResult)NSOrderedDescending;
}
if (value1 < value2)
{
return (NSComparisonResult)NSOrderedAscending;
}
return (NSComparisonResult)NSOrderedSame;
}];
NSLog(@"tmpar2 = %@",tmpAr);
答案 2 :(得分:1)
如果使用initWithKey:ascending:selector:
或sortDescriptorWithKey:ascending:comparator:
创建排序描述符,则可以指定用于比较对象的选择器。
现在问题是哪个选择器要传递。那么你可以在NSString上创建一个Category来实现一个自定义排序函数,该函数根据字符串的数值进行排序。记得从文件:
选择器必须指定由值实现的方法 keyPath标识的属性。用于比较的选择器 传递一个参数,该对象与self进行比较,以及 必须返回适当的NSComparisonResult常量。选择器 必须具有相同的方法签名:
- (NSComparisonResult)localizedCompare:(NSString *)aString
指定属性键的对象,相对于每个对象 集合,必须实现用于创建的比较选择器 排序描述符。如果未指定自定义选择器,则对象必须 实施比较:。
答案 3 :(得分:1)
试试这样: -
NSDictionary *row1 = [NSDictionary dictionaryWithObjectsAndKeys:@"1",@"rowId",nil];
NSDictionary *row2 = [NSDictionary dictionaryWithObjectsAndKeys:@"2",@"rowId",nil];
NSDictionary *row3 = [NSDictionary dictionaryWithObjectsAndKeys:@"3",@"rowId",nil];
NSMutableArray *arr = [[NSMutableArray alloc] initWithObjects:row1,row2,row3,nil];
NSSortDescriptor *desc = [[NSSortDescriptor alloc] initWithKey:@"rowId" ascending:YES];
[arr sortUsingDescriptors:[NSArray arrayWithObject:desc]];
// before sort
NSLog(@"Before %@",arr);
[arr sortedArrayUsingComparator:^(NSDictionary *item1, NSDictionary *item2) {
NSString *first = [item1 objectForKey:@"rowId"];
NSString *second = [item2 objectForKey:@"rowId"];
return [first compare:second options:NSNumericSearch];
}];
// After sort
NSLog(@"After %@",arr);