如何在SQL Server中拆分以破折号分隔的值?

时间:2014-02-15 04:52:13

标签: sql sql-server sql-server-2008

如何只获取表格中的中间部分?我尝试了以下代码,但这只删除了正确的部分...我的输出应该只是中间部分。

例如,当我选择数据1-021514-1时,输出应该是021514,而不是左右虚线

select LEFT(ticketid, CHARINDEX('-', ticketid + '-') + 4) 
from Table

我的数据是:

|TicketID   |
------------
|1-021514-1 |
|10-021514-1|
|2-021514-1 |
|4-021414-1 |

5 个答案:

答案 0 :(得分:2)

请尝试:

SELECT
  LEFT(st, CHARINDEX('-', st)-1) TicketID
from
(
    SELECT
        SUBSTRING(TicketID,  CHARINDEX('-',TicketID)+1, 10000) st
    FROM Table
)x

答案 1 :(得分:1)

试试这个

with t as (select TicketID  as val)
select t.*,
       LEFT(val, charindex('-', val) - 1),
   SUBSTRING(val, charindex('-', val)+1, len(val) - CHARINDEX('-', reverse(val)) - charindex('-', val)),
       REVERSE(LEFT(reverse(val), charindex('-', reverse(val)) - 1))
from t;

(OR)

使用以下功能

CREATE FUNCTION dbo.SplitStrings_CTE(@List nvarchar(max), @Delimiter nvarchar(1))
RETURNS @returns TABLE(val nvarchar(max), [level] int, PRIMARY KEY CLUSTERED([level]))
AS
BEGIN
;WITH cte AS
 (
  SELECT SUBSTRING(@List, 0, CHARINDEX(@Delimiter, @List)) AS val,
         CAST(STUFF (@List + @Delimiter, 1, CHARINDEX(@Delimiter, @List), '') AS nvarchar(max)) AS stval,
         1 AS [level]
  UNION ALL
  SELECT SUBSTRING(stval, 0, CHARINDEX(@Delimiter, stval)),
         CAST(STUFF (stval, 1, CHARINDEX(@Delimiter, stval), '') AS nvarchar(max)),
         [level] + 1
  FROM cte
  WHERE stval != ''
  )
  INSERT @returns
  SELECT REPLACE(val, ' ', '') AS val, [level]
  FROM cte
  RETURN
END

答案 2 :(得分:1)

嗨罗恩试试这个,

   declare @string varchar(25)='1-021514-1'
        declare @val varchar(25)
        SELECT @val= SUBSTRING(@string,  CHARINDEX('-', @string)+1,  ((CHARINDEX('-',@string,(charindex('-',@string)+1))-CHARINDEX('-', @string))-1))
        select @val

答案 3 :(得分:0)

试试这个:

select right(left(ticketid, charindex('-', ticketid, charindex('-', ticketid, 0) + 1) - 1), len(left(ticketid, charindex('-', ticketid, charindex('-', ticketid, 0) + 1) - 1)) - charindex('-', left(ticketid, charindex('-', ticketid, charindex('-', ticketid, 0) + 1) - 1), 0)) from Table

答案 4 :(得分:0)

试试这个

SELECT STUFF(
                STUFF(TicketID,1,CHARINDEX('-',TicketID,1),'')
                ,CHARINDEX('-',STUFF(TicketID,1,CHARINDEX('-',TicketID,1),''),1)
                ,LEN(TicketID)
                ,'') 
        from Table1