我想将NSDate从一个时区转换为另一个时区。
这是我的代码:
NSDate* convertTime(NSDate* fromDate, NSTimeZone* fromTimeZone, NSTimeZone* toTimeZone) {
if (fromTimeZone == toTimeZone) {
return fromDate;
}
NSCalendarUnit val = NSCalendarUnitYear| NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour| NSCalendarUnitMinute | NSCalendarUnitSecond | NSCalendarUnitTimeZone;
NSCalendar* dupCal = [[NSCalendar currentCalendar] copy];
[dupCal setTimeZone:toTimeZone];
NSDateComponents *dupComponents = [dupCal components:val fromDate:fromDate];
return [dupComponents date]; // <- Why return nil?
}
int testTimeZone() {
NSDate* res = convertTime([NSDate date], [NSTimeZone defaultTimeZone], [NSTimeZone timeZoneWithName:@"America/New_York"]);
NSLog(@"convertTime: %@", res);
return 0;
}
在输出窗口中,我可以看到此打印输出:
2014-02-15 11:15:18.040 MyApp[28742:70b] convertTime: (null)
由于某些原因,return [dupComponents date];
总是返回nil,即使我可以在调试器中清楚地看到它已正确初始化。它包含我期望的值。
Printing description of dupComponents:
<NSDateComponents: 0x100112260>
TimeZone: America/New_York (EST) offset -18000
Calendar Year: 2014
Month: 2
Leap month: no
Day: 14
Hour: 19
Minute: 19
Second: 29
为什么会这样?
答案 0 :(得分:19)
我找到了解决方案。
我需要在调用date
之前将日历对象设置为NSDateCompoent对象:
NSDateComponents *dupComponents = [dupCal components:val fromDate:fromDate];
[dupComponents setCalendar:dupCal]; // THIS IS THE SOLUTION
return [dupComponents date];