Question

我有一个如下所示的查询：

SELECT COUNT(*)
FROM members AS t1
INNER JOIN data AS t2
ON t1.ID = t2.ID
WHERE members_id = 1
INTERSECT
SELECT COUNT(*)
FROM members AS t1
INNER JOIN data AS t2
ON t1.ID = t2.ID
WHERE members_id = 2

我想使用group by和order by order：

SELECT COUNT(*), var1
FROM members AS t1
INNER JOIN data AS t2
ON t1.ID = t2.ID
WHERE members_id = 1
INTERSECT
SELECT COUNT(*), var1
FROM members AS t1
INNER JOIN data AS t2
ON t1.ID = t2.ID
WHERE members_id = 2
GROUP BY var1
ORDER BY var1

但是，我得到一个错误，说var1不包含在聚合函数或GROUP BY子句中。有关使用GROUP BY和ORDER BY与intersect命令的任何提示吗？

谢谢！

Answer 1

这是您要尝试实现的查询吗？

SELECT COUNT(*), var1
FROM members AS t1 INNER JOIN
     data AS t2
     ON t1.ID = t2.ID
GROUP BY var1
having sum(case when members_id = 1 then 1 else 0 end)  > 0 and
       sum(case when members_id = 2 then 1 else 0 end)  > 0 ;

这会获得包含两个成员的每个var1的计数。

如何在SQL中使用with by with intersect命令

1 个答案: