传递viewcontroller第二次不起作用

Question

我有一个countryViewController，其中包含列出了不同国家/地区的tableView。单击此按钮将转到phraseViewController。当您第一次单击它时，这可以正常工作，但是当我按下countryViewController中的一行时再次按下并再次测试时。它给了我以下错误：

  

由于未捕获的异常'NSInvalidArgumentException'而终止应用程序，原因：' - [phraseObject name]：无法识别的选择器发送到实例0x948cd60'

为什么我会收到此错误？当它第一次运作时。

代码：

- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qualifiedName attributes:(NSDictionary *)attributeDict 
{
    if ([elementName isEqualToString:@"phrase"]) {
         translation = attributeDict[@"translation"];
         meaning = attributeDict[@"meaning"];
         pronounce = attributeDict[@"pronounce"];
         theId = attributeDict[@"id"];

         object = [phraseObject new];

         object.translation = translation;
         object.meaning = meaning;
         object.pronounce = pronounce;
         object.soId = theId;


         theObject = [noSearchObject new];

         theObject.translation = translation;
         theObject.meaning = meaning;
         theObject.pronounce = pronounce;
         theObject.soId = theId;

         [finalArray addObject:object];
         [noSearchArray addObject:theObject];       
     }

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{    
     static NSString *CellIdentifier = @"Cell";
     UITableViewCell *cell = [tableViewData  dequeueReusableCellWithIdentifier:CellIdentifier];
     cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
     cell.backgroundColor = [UIColor clearColor];
     cell.accessoryView = [[ UIImageView alloc ]
                                 initWithImage:[UIImage imageNamed:@"play2.png" ]];


     if (tableView == self.searchDisplayController.searchResultsTableView) {
         phraseObject *object = self.filterTheArray[indexPath.row];
         cell.textLabel.text = [NSString stringWithFormat:@"%@", object.meaning];
         cell.detailTextLabel.text = [NSString stringWithFormat:@"%@", object.translation];


     } 
     else{        
         noSearchObject *theObject = filteredArray[indexPath.row];
         cell.textLabel.text = [NSString stringWithFormat:@"%@", theObject.meaning];
         cell.detailTextLabel.text = [NSString stringWithFormat:@"%@", theObject.translation];        
     }
     return cell;
 }