Question

我正在进行查询，并且很好地展示了我想要的所有内容：

SELECT prog.cod_go, prog.data, prog.item, prog.tempoexposicao
FROM tb_programacao prog 
JOIN tb_go go ON go.cod_go = prog.cod_go where go.cod_go = '1' 
AND go.equi_func1_mat = '0735'
AND prog.data = '2014-01-24' 
GROUP BY prog.data,prog.item

result:
cod_go | data      | item | tempoexposicao
1      |2014-01-24 | 10   | 00:00:30
1      |2014-01-24 | 11   | 00:00:30
1      |2014-01-24 | 12   | 00:00:30
1      |2014-01-24 | 13   | 00:00:30
1      |2014-01-24 | 14   | 00:00:30
1      |2014-01-24 | 8    | 00:00:30
1      |2014-01-24 | 9    | 00:00:30

之后我尝试了所有这个“tempoexposicao”字段的总和

SELECT SEC_TO_TIME( SUM(TIME_TO_SEC(temp.soma))) AS soma_tudo, temp.cod_go, temp.data, temp.item 
FROM ( SELECT SUM( prog.tempoexposicao) AS 'soma', prog.cod_go, prog.data, prog.item 
FROM tb_programacao prog 
JOIN tb_go go ON go.cod_go = prog.cod_go where go.cod_go = '1'
AND go.equi_func1_mat = '0735' 
AND prog.data = '2014-01-24' 
GROUP BY prog.data,prog.item ) AS temp

result:
soma_tudo | cod_go | data      | item
00:42:00  | 1      |2014-01-24 | 10

我期待00:03:30而不是00:42:00，我不能做这个子查询？

Answer 1

这是您的基本查询：

SELECT prog.cod_go, prog.data, prog.item, prog.tempoexposicao
FROM tb_programacao prog JOIN
    tb_go go
    ON go.cod_go = prog.cod_go
where go.cod_go = '1' AND
     go.equi_func1_mat = '0735' AND
     prog.data = '2014-01-24' 
GROUP BY prog.data, prog.item;

select中有两列不属于group by：prog.item和prog.tempoexposicao的列。这些列的值来自任意匹配行。

此版本应提供一致的结果：

SELECT prog.cod_go, prog.data, min(prog.item) as item, min(prog.tempoexposicao) as tempoexposicao
FROM tb_programacao prog JOIN
    tb_go go
    ON go.cod_go = prog.cod_go
where go.cod_go = '1' AND
     go.equi_func1_mat = '0735' AND
     prog.data = '2014-01-24' 
GROUP BY prog.data, prog.item;

Answer 2

SELECT  SEC_TO_TIME( SUM(TIME_TO_SEC(temp.tempoexposicao))) AS soma_tudo,
temp.cod_go,
temp.data,
temp.item 
FROM(
SELECT
prog.cod_go,
prog.data,
prog.item,
prog.tempoexposicao
FROM tb_programacao prog
JOIN tb_go go ON go.cod_go = prog.cod_go
where go.cod_go = '1'
and go.equi_func1_mat = '0735'
AND prog.data = '2014-01-24'
group by  prog.data,prog.item) AS temp

全部工作！

Answer 3

有效我在子查询中进行连接然后将所有内容作为动态表进行求和谢谢大家

SELECT  SEC_TO_TIME( SUM(TIME_TO_SEC(temp.tempoexposicao))) AS soma_tudo,
temp.cod_go,
temp.data,
temp.item 
FROM(
SELECT
prog.cod_go,
prog.data,
prog.item,
prog.tempoexposicao
FROM tb_programacao prog
JOIN tb_go go ON go.cod_go = prog.cod_go
where go.cod_go = '1'
and go.equi_func1_mat = '0735'
AND prog.data = '2014-01-24'
group by  prog.data,prog.item) AS temp

Sum在我的查询中乘以结果

3 个答案: