如何使用Activity类以外的onActivityResult方法

时间:2014-02-14 13:06:23

标签: android android-activity onactivityresult

我正在创建一个应用程序,我需要找到用户的当前位置。

所以在这里我想做一个任务,比如当用户从该系统意图返回时,我的任务应该在那之后完成。(显示用户当前位置)

所以我打算使用OnActivityResult()

protected void onActivityResult(int requestCode, int resultCode, Intent data) {

}

但问题是我不知道如何在不扩展Activity的类中使用该方法。

请有人告诉我如何实现这一目标?

7 个答案:

答案 0 :(得分:11)

您需要订购活动才能收到结果。

如果仅用于组织代码,则从Activty类调用其他类。

public class Result {
    public static void activityResult(int requestCode, int resultCode, Intent data){
          ...
   }
}


@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
       Result.activityResult(requestCode,resultCode,data);
        ...
    }

答案 1 :(得分:6)

在非Activity类中创建内部类,并在其中定义活动结果处理程序:

class singletonActivity extends Activity{
  protected void onActivityResult(...){
    // do whatever ..
  }
}

将其实例化以调用startActivityForResult

Activity actv = new singletonActivity(..)
actv.startActivityForResult(intent ..)

将调用您的处理程序。 :)

ps:你可能需要包含一些覆盖。把它们留空。

pps:这是老派java mouseListenerAdapter样式 〜乌>

答案 2 :(得分:3)

您无法将此方法称为超出范围。

protected void onActivityResult (int requestCode, int resultCode, Intent data)

如果方法是受保护,就像这种情况一样,您可以看到访问级别表格以了解如何继续。

|-----------------------------------------------------------|
|                     ACCESS LEVELS                         |
|------------------|---------|---------|----------|---------|
|      Modifier    |  Class  | Package | Subclass |  World  |
|------------------|---------|---------|----------|---------|
|      public      |    Y    |    Y    |    Y     |    Y    |
|------------------|---------|---------|----------|---------|
|      protected   |    Y    |    Y    |    Y     |    N    |
|------------------|---------|---------|----------|---------|
|      no modifier |    Y    |    Y    |    N     |    N    |
|------------------|---------|---------|----------|---------|
|      private     |    Y    |    N    |    N     |    N    |
|------------------|---------|---------|----------|---------|

如您所见,此方法只能从android.app.*包,Activity及其子类调用。

<强> SOLUTION:

你需要做这样的事情:

我们有一个班级ImagePicker,用于从图库相机删除中选择图片。如果用户想要删除图片,则此类需要调用onActivityResult(我们不需要为我们已经知道的结果启动Activity。)

public class ImagePicker {
    private ImagePickerDelegate delegate;

    public ImagePicker (ImagePickerDelegate delegate) {
        this.delegate = delegate;
    }

    //Will explain this two methods later
    public void show() {
        //Some code to show AlertDialog
    }

    public void handleResponse(Intent data) {
        //Some code to handle onActivityResult
    }

    //Our interface to delegate some behavior 
    public interface ImagePickerDelegate {
        void onImageHandled(Bitmap image);
        void onImageError();
        void onImageDeleted();
    }
}

要在Activity中使用此类,我们需要实现委托方法并将我们的活动作为ImagePicker的委托传递:

public class MyActivity extends Activity implements ImagePicker.ImagePickerDelegate {
    ImagePicker imagePicker;    

    @OnClick(R.id.image_edit)
    public void selectImage () {
        imagePicker = new ImagePicker(this);
        imagePicker.show();
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (requestCode == ImagePicker.REQUEST_IMAGE_PICKER && resultCode == RESULT_OK) {
            imagePicker.handleResponse(data);
        }
        super.onActivityResult(requestCode, resultCode, data);
    }

    @Override
    public void onImageHandled(Bitmap image) {
        //handle image resized
        imageView.setImageBitmap(image);
    }

    @Override
    public void onImageError() {
        //handle image error
        Toast.makeText(this, "Whoops - unexpected error!", Toast.LENGTH_SHORT).show();
    }

    @Override
    public void onImageDeleted() {
        //handle image deleted
        groupImageView.setImageBitmap(null);
        groupImageView.setImageResource(R.drawable.ic_pick_picture);
    }
}

最后,我们需要调用thous委托方法,这种方法发生在show()handleResponse(Intent data)中:

//The show method create and dialog with 3 options,
//the important thing here, is when an option is selected
public void show() {
    //Inflating some views and creating dialog...

    NavigationView navView = (NavigationView)viewInflated.findViewById(R.id.navigation_menu);
    navView.setNavigationItemSelectedListener( new NavigationView.OnNavigationItemSelectedListener() {
        @Override
        public boolean onNavigationItemSelected(MenuItem menuItem) {
            switch (menuItem.getItemId()) {
                case R.id.action_select_image:
                    Intent pickPhoto = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
                    activity.startActivityForResult(pickPhoto , REQUEST_IMAGE_PICKER);
                    break;
                case R.id.action_take_picture:
                    Intent takePicture = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
                    activity.startActivityForResult(takePicture, REQUEST_IMAGE_PICKER);
                    break;
                case R.id.action_delete_image:
                    delegate.onImageDeleted(); //send response to activity
                    break;
            }
            alertDialog.dismiss();
            return true;
        }
    });

    //Show dialog...
}


//this method is called from onActivityResult
public void handleResponse(Intent data) {
    try {
        //Retrieve and resize image...
        delegate.onImageHandled(image); //send the image to activity
    } catch (Exception e) {
        e.printStackTrace();
        delegate.onImageError(); //send error to activity
    }
}

最后,我们拥有class,可以在Activity而不是onActivityResult中调用方法,但是当您在onActivityResult中获得结果时,你需要在class

中处理它

答案 3 :(得分:1)

您需要在此课程中注册Activity,然后使用OnActivityResult()进行该活动。

答案 4 :(得分:1)

当您使用活动中的startActivityForResult方法启动活动时,只有调用者才会返回结果。

因此,您可以处理结果并将其传递给任务或更新该活动的UI:

int MY_REQUEST_ID = 1;

public void onClick(){
    //Select a contact.
    startActivityForResult(
             new Intent(Intent.ACTION_PICK,
             new Uri("content://contacts")),
             MY_REQUEST_ID);
}    

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
     if(requestCose == MY_REQUEST_ID && resultCode == SUCCESS) {
         MyAsyncTask task = new AsyncTask(requestCode, resultCode, data);
         task.execute();
         // or update the UI
         textView.setText("Hi, activity result: "+ resultCode);
     }
}

答案 5 :(得分:0)

我正在这样使用它,这可能对其他人有帮助

我的片段中有

// Upload Cover Photo On Button Click
btn.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

        // Start The Image Cropper And Go To onActivityResult
        Intent intent = ImageManager.startImageCropper(getContext());
        startActivityForResult(intent, CropImage.CROP_IMAGE_ACTIVITY_REQUEST_CODE);

    }
});

然后在片段中调用这样的结果

// On Activity Result for Start Activity For Result
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {

    super.onActivityResult(requestCode, resultCode, data);

    // Get The Image From Image Cropper
    Uri resultUri = ImageManager.activityResult(requestCode, resultCode, data, getContext());
}

支持这些的公共类/功能是

public class ImageManager {

    // Start Image Cropper
    public static Intent startImageCropper(Context context) {

        // Crop Image
        Intent intent = CropImage.activity()
                .setGuidelines(CropImageView.Guidelines.ON)
                .setActivityTitle("Title")
                .setCropMenuCropButtonTitle("Save")
                .setAutoZoomEnabled(true)
                .setAspectRatio(1, 1)
                .getIntent(context);

        return intent;

    }

    public static Uri activityResult(int requestCode, int resultCode, Intent data, Context context) {

        // Handle Cropped Image

        Uri resultUri = null;

        if (requestCode == CropImage.CROP_IMAGE_ACTIVITY_REQUEST_CODE) {
            CropImage.ActivityResult result = CropImage.getActivityResult(data);
            if (resultCode == Activity.RESULT_OK) {
                resultUri = result.getUri();

            } else if (resultCode == CropImage.CROP_IMAGE_ACTIVITY_RESULT_ERROR_CODE) {
                Exception error = result.getError();
                Toast.makeText(context, (CharSequence) error, Toast.LENGTH_SHORT).show();
            }

        }
        return resultUri;
    }
}

答案 6 :(得分:-2)

最后,我得到了我需要的东西以及这个问题的解决方案。

 Activity con;
Intent intent_= new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
            con.startActivityForResult(intent_, 0);

现在我可以在这里创建一个方法,

public void startActivityForResult(Intent i, int code)
{
    Log.e("", "insede method startActivityForResult()");
}

通过使用此系统不会为我的意图创建子活动,因此,只有在用户从意图返回后才会调用此方法。