Question

我的代码如下：

if len(sys.argv)>1:
    host = sys.argv[1]
    number = sys.argv[2] if len(sys.argv)>2 else "1"
    size = sys.argv[3] if len(sys.argv)>3 else "56"
    timeout = sys.argv[4] if len(sys.argv)>4 else "1"

        proc = subprocess.Popen(["ping \"" + host + "\" -c \"" + number + "\" -s \"" + size + "\" -W \"" + timeout + "\" 2>/dev/null | grep packets | sed 's/[^0-9,%]*//g'"], stdout=subprocess.PIPE, shell=True)
        (out, err) = proc.communicate()

    print "address=\"" + host + "\" data=" + out

我需要拆分列表。我怎么能做到这一点？
我尝试的所有内容都会导致错误：cannot concatenate 'str' and ... objects

就像我尝试的那样：

...
    res=list(out)
        print "address=\"" + host + "\" data=" + res

我收到了错误：

TypeError: cannot concatenate 'str' and 'list' objects

Answer 1

要统一字符串和列表，首先必须从列表中删除字符串：

    res=list(out)
    print "address=\"" + str(host) + "\" data=" + str(res)

subprocess，无法连接'str'和...对象

1 个答案: