Question

如果下面使用dm_exec_procedure_stats的查询的[Total Duration（s）]列给出了查询返回结果所需的平均时间，那么任何人都可以进行混淆吗？我担心这只是这些查询重新调整结果所花时间的一个因素，因为它们看起来很低。

感谢每个花时间看的人。

任何帮助或建议将不胜感激

SELECT SUBSTRING(qt.TEXT, CHARINDEX('USP_', qt.TEXT, 1), CHARINDEX(']', qt.TEXT, CHARINDEX('USP_', qt.TEXT, 1)) - CHARINDEX('USP_', qt.TEXT, 1)) AS Procedure_Name,
       qt.TEXT,
       CAST(total_elapsed_time / 1000000.0 AS DECIMAL(28, 2))                                                                                    AS [Total Duration (s)],
       CASE
         WHEN execution_count = 0 THEN 0
         ELSE CAST(total_worker_time * 100.0 / total_elapsed_time AS DECIMAL(28, 2))
       END                                                                                                                                       AS [% CPU],
       CASE
         WHEN execution_count = 0 THEN 0
         ELSE CAST(( total_elapsed_time - total_worker_time ) * 100.0 / total_elapsed_time AS DECIMAL(28, 2))
       END                                                                                                                                       AS [% Waiting],
       execution_count,
       CASE
         WHEN execution_count = 0 THEN 0
         ELSE CAST(total_elapsed_time / 1000000.0 / execution_count AS DECIMAL(28, 2))
       END                                                                                                                                       AS [Average Duration (s)],
       sql_handle,
       plan_handle,
       object_id,
       total_elapsed_time,
       total_worker_time,
       execution_count,
       total_physical_reads,
       total_logical_reads,
       total_logical_writes
FROM   sys.dm_exec_procedure_stats qs
       CROSS APPLY sys.dm_exec_sql_text(qs.sql_handle) AS qt
WHERE  qt.text LIKE '%USP%'

ORDER  BY 1

Answer 1

要获得平均时间，您需要除以TOTAL / COUNT然后除以1000000.0以获得秒数。

这是代码：

,CONVERT(DECIMAL(26,10),(qs.total_elapsed_time / qs.execution_count)) / 1000000.0 AS [avg_elapsed_time_inSec]

sys.dm_exec_procedure_stats - 我正确地解释它

1 个答案: