我有一个C#字典Dictionary<MyKey, MyValue>
,我希望根据Dictionary<MyKey, MyValue>
将其拆分为MyKey.KeyType
的集合。 KeyType
是一个枚举。
然后我会留下一个包含键值对的字典,其中MyKey.KeyType = 1
和另一个字典MyKey.KeyType = 2
,等等。
有没有一种很好的方法,比如使用Linq?
答案 0 :(得分:9)
var dictionaryList =
myDic.GroupBy(pair => pair.Key.KeyType)
.OrderBy(gr => gr.Key) // sorts the resulting list by "KeyType"
.Select(gr => gr.ToDictionary(item => item.Key, item => item.Value))
.ToList(); // Get a list of dictionaries out of that
如果你想要一个最后用“KeyType”键入的词典字典,方法是类似的:
var dictionaryOfDictionaries =
myDic.GroupBy(pair => pair.Key.KeyType)
.ToDictionary(gr => gr.Key, // key of the outer dictionary
gr => gr.ToDictionary(item => item.Key, // key of inner dictionary
item => item.Value)); // value
答案 1 :(得分:1)
我相信以下内容会有效吗?
dictionary
.GroupBy(pair => pair.Key.KeyType)
.Select(group => group.ToDictionary(pair => pair.Key, pair => pair.Value);
答案 2 :(得分:0)
所以你真的想要一个IDictionary<MyKey, IList<MyValue>>
类型的变量?
答案 3 :(得分:0)
您可以使用GroupBy Linq函数:
var dict = new Dictionary<Key, string>
{
{ new Key { KeyType = KeyTypes.KeyTypeA }, "keytype A" },
{ new Key { KeyType = KeyTypes.KeyTypeB }, "keytype B" },
{ new Key { KeyType = KeyTypes.KeyTypeC }, "keytype C" }
};
var groupedDict = dict.GroupBy(kvp => kvp.Key.KeyType);
foreach(var item in groupedDict)
{
Console.WriteLine("Grouping for: {0}", item.Key);
foreach(var d in item)
Console.WriteLine(d.Value);
}
答案 4 :(得分:0)
除非您只想拥有单独的集合:
Dictionary myKeyTypeColl<KeyType, Dictionary<MyKey, KeyVal>>
答案 5 :(得分:0)
Dictionary <int,string> sports;
sports=new Dictionary<int,string>();
sports.add(0,"Cricket");
sports.add(1,"Hockey");
sports.add(2,"Badminton");
sports.add(3,"Tennis");
sports.add(4,"Chess");
sports.add(5,"Football");
foreach(var spr in sports)
console.WriteLine("Keu {0} and value {1}",spr.key,spr.value);
输出:
Key 0 and value Cricket
Key 1 and value Hockey
Key 2 and value Badminton
Key 3 and value Tennis
Key 4 and value Chess
Key 5 and value Football