使用正则表达式使用Grep命令

Question

  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x100
  Delay: 10x10

上面是我的txt文件的数据如何在延迟之后获取记录：在x100之前。请告诉我确切的语法？

Answer 1

awk -F"[:x]” '$NF==100{ print $2 }' txt.file

Answer 2

如果你有GNU grep，实际上可以用grep完成。

grep -Po '^Delay: \K[1-9][0-9]*' filename