Question

作为一个赋值，我应该为分数创建一个Rational类，并重载各种运算符以操作分数。但是我在解决如何做到这一点时遇到了很多麻烦。这是我的代码和当前的错误消息。任何帮助将不胜感激！

编辑：感谢您的帮助。它仍然有两个错误消息。一大堆（14+）个实例：未定义引用'Rational :: Rational（）' 2：当我超载＆lt;＆lt;运算符它表示num和den未定义。如何告诉它从应该打印的对象中获取num和den？谢谢！

头文件

#ifndef Rational_H
#define Rational_H

#include<iostream>
#include <string>
using namespace std;

class Rational
{

    friend Rational operator+(const Rational& x1, const Rational& x2);
    friend Rational operator-(const Rational& x1, const Rational& x2);
    friend Rational operator*(const Rational& x1, const Rational& x2);

public:
    Rational(); //constructor
    void setFraction(int, int); //set fractional
    int getNum() const;
    int getDen() const;

    void RSimplify();
    void printFraction();
    friend ostream &operator<<( ostream &, const Rational & );
    friend istream &operator>>( istream &, Rational & );

private:
    int num;
    int den;
 };

#endif

.cpp文件

#include <iomanip>
#include "Rational.h"
using namespace std;


int Rational::getNum() const
{
    return num;
}

int Rational::getDen() const
{
    return den;
}

ostream &operator<<(ostream &output, const ATJRational &ATJRational)
{
    return output << num << "/" << den;
Error: num and den are not declared in this scope
}
istream &operator>>( istream &input, ATJRational &ATJRational)
{
    char slash;
    return input >> ATJRational.num >> slash >> ATJRational.den;
    ATJRational.RSimplify();
}

void ATJRational::RSimplify()
{
    for(int i=2; i<14; i++)
    {
        while(den % i == 0)
        {
            if(num % i == 0)
            {
                den = den / i;
                num = num / i;
            }
        }
    }
}


Rational operator+(const Rational& x1, const Rational& x2)
   {
     Rational x3;     
     x3.num = (x1.num * x2.den) + (x2.num * x1.den);
     x3.den = (x1.den * x2.den);
     x3.RSimplify();
     return x3;
   }

Rational operator-(const Rational& x1, const Rational& x2)
   {
     Rational x3;      // result
     x3.num = (x1.num * x2.den) - (x2.num * x1.den);
     x3.den = (x1.den * x2.den);
     x3.RSimplify();
     return x3;
   }

Rational operator*(const Rational& x1, const Rational& x2)
   {
     Rational x3;      // result
     x3.num = (x1.num * x2.num);
     x3.den = (x1.den * x2.den);
     x3.RSimplify();
     return x3;
   }

主档

#include <iostream>
#include "Rational.h"
using namespace std;

int main()
{
    Rational x1; //create object fraction
    Rational x2;
    Rational x3;

    cout<<"Enter a fraction in the form 1/4:"<<endl;
    cin>>x1;

    cout<<"Enter a 2nd fraction in the form 1/4:"<<endl;
    cin>>x2;

    cout<<"The two fractions in their lowest terms are: "<<x1<<" and "<<x2<<endl;

    cout<<"Adding the 1st and 2nd fractions together..."<<endl;
    x3 = x1 + x2;
    cout<<"The sum of the two fractions is:"<<x3<<endl;

    cout<<"Subtracting the 1st fraction from the 2nd fraction..."<<endl;
    x3 = x2 - x1;
    cout<<"The result is:"<<x3<<endl;

    cout<<"Multiplying the 1st fraction by the 2nd fraction..."<<endl;
    x3 = x1 * x2;
    cout<<"The product is:"<<x3<<endl;

}

Answer 1

忽略任何逻辑错误，我可以看到一些问题。可能会有更多。

首先，这个

RSimplify.x3;

应该是

x3.RSimplify();

其次，算术运算符定义与好友声明不匹配。您缺少RHS的const：

Rational operator+(const Rational& x1, Rational& x2) { .... }

需要

Rational operator+(const Rational& x1, const Rational& x2) { .... }

第三，输出流操作符应该对您传递的流进行操作，而不是显式cout。所以，

ostream &operator<<(ostream &output, const Rational &Rational)
{
    return output << num << "/" << den;
}

请注意，将其留给调用者添加endl或其他任何内容也是明智的。

分数类故障排除

1 个答案: