Question

我正在尝试将列表ConnectedAtoms分配给新创建的server_st记录中的列表connectedatoms。但是我得到了一个糟糕的错误。

-module(server).
-export([loop/2, initial_state/1]).

-include_lib("./defs.hrl").


loop(St,{tryConnect,Atom}) -> 
    IsConnected = funcs:hasElem(St#server_st.connectedatoms,Atom),
    if
        IsConnected==true -> 
            {'EXIT',user_already_connected};
        IsConnected==false -> 
            ConnectedAtoms = St#server_st.connectedatoms ++ [Atom],
            St = #server_st{servername=St#server_st.servername,connectedatoms=ConnectedAtoms},
            {"Connected!",St}
    end;

loop(St, _Msg) ->
   io:format("Server got message.~n"),
   {ok, St}.



initial_state(_Server) ->
    #server_st{servername=_Server,connectedatoms=[]}.

Answer 1

当您尝试将值重新分配给St.时，会出现错误匹配错误。由于Erlang是一种函数式编程语言，因此一旦为变量赋值，就无法更改该值。一旦变量绑定到某个值，接下来'='运算符只匹配模式。

St = #server_st{servername=St#server_st.servername,connectedatoms=ConnectedAtoms},

将其更改为其他变量

StConnected = #server_st{servername=St#server_st.servername,connectedatoms=ConnectedAtoms},

将列表分配给记录时，Erlang，badmatch错误

1 个答案: