#!/usr/bin/python
import csv
import re
string_1 = ('OneTouch AT')
string_2 = ('LinkRunner AT')
string_3 = ('AirCheck')
#searched = ['OneTouch AT', 'LinkRunner AT', 'AirCheck']
print "hello Pythong! "
#def does_match(string):
# stringl = string.lower()
# return any(s in stringl for s in searched)
inFile = open('data.csv', "rb")
reader = csv.reader(inFile)
outFile = open('data2.csv', "wb")
writer = csv.writer(outFile, delimiter='\t', quotechar='"', quoting=csv.QUOTE_ALL)
for row in reader:
found = False
for col in row:
if col in [string_1, string_2, string_3] and not found:
writer.writerow(row)
found = True
#for row in reader:
# if any(does_match(col) for col in row):
# writer.writerow(row[:2]) # write only 2 first columns
inFile.close()
outFile.close()
我正在试图弄清楚如何在CSV文件中搜索3个项目。如果存在这些项目则打印该行。理想情况下,我希望只将第1列和第3列打印到新文件中。
示例数据文件
LinkRunner AT Video,10,20
Wireless Performance Video OneTouch AT,1,2
Wired OneTouch AT,200,300
LinkRunner AT,200,300
AirCheck,200,300
答案 0 :(得分:3)
我正在试图弄清楚如何在CSV文件中搜索3个项目。如果 那些项目存在打印行。理想情况下,我只想要第1列 和3打印到新文件。
试试这个:
import csv
search_for = ['OneTouch AT','LinkRunner AT','AirCheck']
with open('in.csv') as inf, open('out.csv','w') as outf:
reader = csv.reader(inf)
writer = csv.writer(outf, delimiter='\t', quotechar='"', quoting=csv.QUOTE_MINIMAL)
for row in reader:
if row[0] in search_for:
print('Found: {}'.format(row))
writer.writerow(row)
答案 1 :(得分:0)
#!/usr/bin/python
import csv
import numpy as np
class search_csv(object):
def __init__(self, infile, outfile):
infile = open(infile, 'rb')
read_infile = [i for i in csv.reader(infile, delimiter='\t', quotechar='"', quoting=csv.QUOTE_MINIMAL)]
self.non_numpy_data = read_infile
self.data = np.array(read_infile, dtype=None)
self.outfile = open(outfile, 'wb')
self.writer_ = csv.writer(self.outfile, delimiter='\t', quotechar='"', quoting=csv.QUOTE_MINIMAL)
def write_to(self, matched_values):
self.writer_.writerows(matched_values)
print ' Matched Values Written '
return True
def searcher(self, items, return_cols=[0,2]): ##// items should be passed as list -> ['OneTouch AT', 'LinkRunner AT', 'AirCheck']
find_these = np.array(items, dtype=None)
matching_y = np.in1d(self.data, find_these).reshape(self.data.shape).nonzero()[0]
matching_data = self.data[matching_y][:,return_cols]
self.write_to(matching_data)
self.outfile.close()
return True
def non_numpy_search(self, items, return_cols=[0,2]):
lst = []
for i in self.non_numpy_data:
for ii in items:
if ii in i:
z = []
for idx in return_cols:
z.append(i[idx])
lst.append(z)
break
self.write_to(lst)
return True
### now use the class ###
SEARCHING_FOR = ['OneTouch AT', 'LinkRunner AT', 'AirCheck']
IN_FILE = 'in_file.csv'
OUT_FILE = 'out_file.csv'
non_numpy_search(IN_FILE, OUT_FILE).non_numpy_search(SEARCHING_FOR)
通过你的问题的措辞,我假设你只是想完成手头的任务,而不是真正关心如何。因此,将其复制并粘贴并将您的数据文件用作“IN_FILE”值,并将要写入的文件名用作“OUT_FILE”值。完成后,将要搜索的值放在“SEARCHING_FOR”列表中。
注意事项...... SEARCHING_FOR应该是一个列表。
SEARCHING_FOR中的值完全匹配,因此“A”与“a”不匹配。如果你想要使用正则表达式或更复杂的东西,请告诉我。
在函数'non_numpy_search'中有一个'return_cols'参数。它默认为第一列和第三列。
如果你没有numpy,请告诉我。
答案 2 :(得分:0)
#!/usr/bin/python
import csv
import re
import sys
import gdata.docs.service
#string_1 = ('OneTouch AT')
#string_2 = ('LinkRunner AT')
#string_3 = ('AirCheck')
searched = ['aircheck', 'linkrunner at', 'onetouch at']
def find_group(row):
"""Return the group index of a row
0 if the row contains searched[0]
1 if the row contains searched[1]
etc
-1 if not found
"""
for col in row:
col = col.lower()
for j, s in enumerate(searched):
if s in col:
return j
return -1
def does_match(string):
stringl = string.lower()
return any(s in stringl for s in searched)
#Opens Input file for read and output file to write.
inFile = open('data.csv', "rb")
reader = csv.reader(inFile)
outFile = open('data2.csv', "wb")
writer = csv.writer(outFile, delimiter='\t', quotechar='"', quoting=csv.QUOTE_ALL)
#for row in reader:
# found = False
# for col in row:
# if col in [string_1, string_2, string_3] and not found:
# writer.writerow(row)
# found = True
"""Built a list of items to sort. If row 12 contains 'LinkRunner AT' (group 1),
one stores a triple (1, 12, row)
When the triples are sorted later, all rows in group 0 will come first, then
all rows in group 1, etc.
"""
stored = []
for i, row in enumerate(reader):
g = find_group(row)
if g >= 0:
stored.append((g, i, row))
stored.sort()
for g, i, row in stored:
writer.writerow(tuple(row[k] for k in (0,2))) # output col 1 & 5
#for row in reader:
# if any(does_match(col) for col in row):
# writer.writerow(row[:2]) # write only 2 first columns
# Closing Input and Output files.
inFile.close()
outFile.close()