Question

我是Android新手，请帮助我。

如果启用了以下代码中的两个复选框，我怎样才能实现打印值？

public EditText output;
Button one;

int a;
CheckBox check,check1;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    output =(EditText)findViewById(R.id.editText1);
    one=(Button)findViewById(R.id.button1);
    check  = (CheckBox)this.findViewById(R.id.checkbox1);
    check1 = (CheckBox)this.findViewById(R.id.checkbox2);

    check.setOnClickListener(new OnClickListener() {

          public void onClick(View v) {
                    //is chkIos checked?
            if (((CheckBox) v).isChecked()) {
                a=100;

            }
            else{
                a=0;
            }
               }
                      });

    check1.setOnClickListener(new OnClickListener() {

          public void onClick(View v) {
                    //is chkIos checked?
            if (((CheckBox) v).isChecked()) {
                a=100;
            }
            else{
                a=0;
            }
          }
});


//this statment is wrong.    if((check.isChecked() == true)&&(check.isChecked() == true)){

        a=200;
    }

 one.setOnClickListener(new View.OnClickListener() {  

       public void onClick(View v) {                 
            if(v==one){
              output.setText(""+a);
            }
       }
});
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}

}

Answer 1

    public void onCheckboxClicked(View view) {
    // Is the view now checked?
    boolean checked = ((CheckBox) view).isChecked();

    // Check which checkbox was clicked
    switch(view.getId()) {
        case R.id.checkbox_meat:
            if (checked)
                // Put some meat on the sandwich
            else
                // Remove the meat
            break;
        case R.id.checkbox_cheese:
            if (checked)
                // Cheese me
            else
                // I'm lactose intolerant
            break;
        // TODO: Veggie sandwich
    }
}

Answer 2

在按钮的onClick方法

if((checkBox1.isChecked()) && (checkBox2.isChecked)){
     editText.setText("Both are checked");
}

我们不需要分配任何变量，因为isChecked方法返回一个布尔值，因此可以直接在里面检查if。

Answer 3

将两个复选框声明为final，并与

进行比较

if (check.isChecked() == true && check1.isChecked == true)

就我而言，它有效。示例：检查按钮的OnClick方法中的复选框的状态

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    final CheckBox check = (CheckBox)findViewById(R.id.check);
    Button button1 = (Button)findViewById(R.id.button1);

    button1.setOnClickListener(new OnClickListener() {

          public void onClick(View v) {
              Log.d("Tag-test", "Value:" + check.isChecked());
          }
    });
}

Answer 4

This is my new code

public EditText output;
Button one;

int a;
CheckBox check,check1;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
output =(EditText)findViewById(R.id.editText1);
    one=(Button)findViewById(R.id.button1);
     check  = (CheckBox)this.findViewById(R.id.checkbox1);
     check1 = (CheckBox)this.findViewById(R.id.checkbox2);

     one.setOnClickListener(new View.OnClickListener() {  
         public void onClick(View v)
         {
             if(check.isChecked()){a=100;}
             else{a=0;}
             if(check1.isChecked()){a=100;}
             else{a=0;}

              if(check.isChecked()&& check1.isChecked())
              {
                  a=200;
              }
              else{a=0;}
              if(v==one)
              {
                  output.setText(""+a);
                  }

         }});

如何比较android上的两个复选框值？

4 个答案: