Question

我有以下表格。

CREATE TABLE `cms_compound` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `nomenclature` varchar(50) DEFAULT NULL,
  `version_number` bigint(20) DEFAULT NULL,
  `version_region_id` bigint(20) DEFAULT NULL,
  PRIMARY KEY (`id`)
);

CREATE TABLE `cms_compound_disease` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `compound_id` bigint(20) NOT NULL,
  `disease_id` bigint(20) NOT NULL,
  PRIMARY KEY (`id`)
);

CREATE TABLE `cms_disease` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `title` varchar(50) DEFAULT NULL,
  `acronym` varchar(50) DEFAULT NULL,
  `version_number` bigint(20) DEFAULT NULL,
  `version_region_id` bigint(20) DEFAULT NULL,
  PRIMARY KEY (`id`)
);

CREATE TABLE `cms_version_region` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `version_id` bigint(20) NOT NULL,
  `region_id` bigint(20) NOT NULL,
  PRIMARY KEY (`id`)
);

我正在使用以下查询

SELECT SQL_CALC_FOUND_ROWS 
    c.id, 
    c.nomenclature, 
    d.acronym
FROM 
    compound c 
LEFT JOIN 
    compound_disease cd ON (cd.compound_id = c.id) 
LEFT JOIN 
    disease d ON (cd.disease_id = d.id) 
LEFT JOIN 
    version_region vr ON (vr.id = c.version_region_id) 
WHERE 
    c.version_number = 2 AND vr.version_id = 2 AND vr.region_id = 1 
LIMIT 0, 10

这给了我以下结果。

+-----+--------------+---------+
| id  | nomenclature | acronym |
+-----+--------------+---------+
| 155 | AEB071       | ALL     |
| 155 | AEB071       | AML     |
| 155 | AEB071       | AdCC    |
| 156 | Nilotinib    | NULL    |
| 161 | Buparlisib   | NULL    |
| 162 | BYL719       | NULL    |
+-----+--------------+---------+

请注意，155之后会重复命名AEB071的ID LEFT JOIN。

我想要以下结果（首字母缩略词连接）

+-----+--------------+--------------------+
| id  | nomenclature | acronym            |
+-----+--------------+--------------------+
| 155 | AEB071       | ALL, AML, AdCC     |
| 156 | Nilotinib    | NULL               |
| 161 | Buparlisib   | NULL               |
| 162 | BYL719       | NULL               |
+-----+--------------+--------------------+

如何使用MySQL查询执行此操作？

Answer 1

使用GROUP_CONCAT()：

SELECT SQL_CALC_FOUND_ROWS 
    c.id, 
    c.nomenclature, 
    GROUP_CONCAT(d.acronym) 
FROM 
    compound c 
LEFT JOIN 
    compound_disease cd ON (cd.compound_id = c.id) 
LEFT JOIN 
    disease d ON (cd.disease_id = d.id) 
LEFT JOIN 
    version_region vr ON (vr.id = c.version_region_id) 
WHERE 
    c.version_number = 2 AND vr.version_id = 2 AND vr.region_id = 1 
GROUP BY
  c.id,
  c.nomenclature

连接MySQL中的行

1 个答案: