Question

我不明白为什么在编译代码时出现此错误。我相信我所做的一切都和以前一样，但这次不行。

stack.cpp:30: error: cannot convert 'record*' to 'record**' for argument '2' to 'void filename(char*, record**)'

编译时会有更多错误，但我会解决它们。（我也必须（每行添加4个代表“代码”的空格，所以如果有其他人可以告诉我如何自动完成！那就太棒了！

#include <iostream>
#include <cstdlib>
#include <fstream>
#include <stdio.h>
#include <cstring>
#include <strings.h>

using namespace std;

struct record
{
    char first [20];
    char mid   [1];
    char last  [20];
    int  ssn;
};

void filename (char ifname [], struct record* student[]);
void structfill (fstream & infile, struct  record*  student []);

int main ()
{

    system ("clear");

    fstream infile;
    char ifname [256];
    struct record * student;
    filename (ifname, student);

    return 0;
}
/*******************************************************************/
void filename (char ifname [],record* student [])
{
    fstream infile;
    cout << "Enter name of file to read from: ";
    cin.getline (ifname, 256);
    cout << endl;
    infile.open (ifname);
    if (!infile.is_open ())
    {
        cerr << "FILELOOP!: Unable to open input file " << ifname
        << endl;
        exit (1);
    }
    structfill (infile, student);
}
/*******************************************************************/
void structfill (fstream & infile, record* student [])
{

    char buffer [81];
    char buffername [81];
    char bufferfirst [81];
    int n=0;
    int x=0;
    int f=0;

    infile.getline (buffer,81);
    while (!infile.eof ())
    {
        x++;
        cout << "-----------------------" << x;
        if (strncasecmp (buffer, "<student>",9)==0)
        {
            n++;
            cout << "jess sucks" << n;
            student = new *record;
            infile.getline (buffername, 81);
            if (strncasecmp (buffername, "<first>",7)==0)
            {
                f++;
                infile.getline (bufferfirst, 81);
                strcpy (student->first, bufferfirst);
                cout << endl << "######  " << f;
            }
        }
        infile.getline (buffer, 81);
        cout << *student[n]->first;
        cout << "endendendend" << endl;
    }
}

Answer 1

传递时，数组衰减为指向第一个元素的指针：

void structfill (fstream & infile, record*  student);

此外，删除C-isms。这里不需要指定“struct”。

Answer 2

这是无错误的代码。我成功编译了它

#include <iostream>
#include <cstdlib>
#include <fstream>
#include <stdio.h>
#include <cstring>
#include <strings.h>


using namespace std;

struct record
{
    char first [20];
    char mid   [1];
    char last  [20];
    int  ssn;
};

void filename (char ifname [], struct record* student);
void structfill (fstream & infile, struct  record*  student);

int main ()
{

    system ("clear");

    fstream infile;
    char ifname [256];
    struct record * student;
    filename (ifname, student);

    return 0;
}
/*******************************************************************/
void filename (char ifname [],record* student )
{
    fstream infile;
    cout << "Enter name of file to read from: ";
    cin.getline (ifname, 256);
    cout << endl;
    infile.open (ifname);
    if (!infile.is_open ())
    {
        cerr << "FILELOOP!: Unable to open input file " << ifname
        << endl;
        exit (1);
    }
    structfill (infile, student);
}
/*******************************************************************/
void structfill (fstream & infile, record* student )
{

    char buffer [81];
    char buffername [81];
    char bufferfirst [81];
    int n=0;
    int x=0;
    int f=0;

    infile.getline (buffer,81);
    while (!infile.eof ())
    {
        x++;
        cout << "-----------------------" << x;
        if (strncasecmp (buffer, "<student>",9)==0)
        {
            n++;
            cout << "jess sucks" << n;
            student = new struct record;
            infile.getline (buffername, 81);
            if (strncasecmp (buffername, "<first>",7)==0)
            {
                f++;
                infile.getline (bufferfirst, 81);
                strcpy (student->first, bufferfirst);
                cout << endl << "######  " << f;
            }
        }
        infile.getline (buffer, 81);
        cout << student[n].first;
        cout << "endendendend" << endl;
    }
}

New运算符返回一个指针而不是object.You应该使用struct record。
学生能够持有一个结构记录数组。

错误：无法将'record *'转换为'record **'

2 个答案: