如何生成斐波纳契数列

时间:2014-02-13 05:37:31

标签: sql sql-server

如何在sql中生成Fibonacci系列!

我需要生成Fibonacci系列0 1 1 2 3 5 8 13 21 ... N

我使用C代码轻松地完成了这项工作,我需要使用Sql执行此操作!

6 个答案:

答案 0 :(得分:14)

尝试此简单查询:

1)逐行结果(单列,多行)

WITH Fibonacci (PrevN, N) AS
(
     SELECT 0, 1
     UNION ALL
     SELECT N, PrevN + N
     FROM Fibonacci
     WHERE N < 1000000000
)
SELECT PrevN as Fibo
     FROM Fibonacci
     OPTION (MAXRECURSION 0);

输出1:

enter image description here

2)仅针对一行中的结果(逗号拼写,单个单元格中)

WITH Fibonacci (PrevN, N) AS
(
 SELECT 0, 1
    UNION ALL
    SELECT N, PrevN + N
    FROM Fibonacci
    WHERE N < 1000000000
)
SELECT Substring(
    (SELECT cast(', ' as varchar(max)) + cast(PrevN as varchar(max)
);
FROM Fibonacci
FOR XML PATH('')),3,10000000) AS list

输出2: enter image description here

答案 1 :(得分:4)

试试这个!

declare @a int
declare @b int
declare @c int
Declare @i int

set @a=0
set @b=1
set @i=0
set @c=0
Print 'Fibonacci Series'
print @a
print @b
while @i<10 
Begin
set @c=@a+@b
print @c
set @i=@i+1
set @a=@b
set @b=@c
end

输出!

Fibonacci Series

0 1 1 2 3 五 8 13 21 34 55 89

答案 2 :(得分:3)

请尝试:

SELECT 0  AS fib_number UNION ALL
SELECT
    FLOOR(POWER(( 1 + SQRT(5) ) / 2.0, number) / SQRT(5) + 0.5)
FROM master..spt_values
WHERE TYPE = 'p' AND number BETWEEN 1 AND 70

答案 3 :(得分:3)

试试这个: -

 Declare @Fib int = 5
 ;with cte as
 (
   Select 0 as Previous,1 as Next ,0 as Level 
   union all
   Select Next,Next + Previous,Level +1 from cte 
   where Level +1 <@Fib
 )
 Select Previous as FibonacciSeries from cte

答案 4 :(得分:0)

这是用于生成系列中的前10个数字。

DECLARE @NoOne INT,  @NoTwo INT
DECLARE @FibonacciTable TABLE (Number INT NOT NULL)
--Insert first two numbers 0 and 1
INSERT @FibonacciTable (Number) SELECT 0 UNION ALL SELECT 1
SELECT @NoOne = 0, @NoTwo = 1

WHILE (SELECT COUNT(*) FROM @FibonacciTable) < 10
BEGIN
    INSERT @FibonacciTable (Number) VALUES(@NoOne + @NoTwo)
    SELECT @NoTwo = @NoOne + @NoTwo, @NoOne = @NoTwo - @NoOne
END
SELECT * FROM @FibonacciTable   
GO

答案 5 :(得分:0)

CREATE TABLE #Fibonacci (value BIGINT)
GO

INSERT INTO #Fibonacci(value) SELECT 0
INSERT INTO #Fibonacci(value) SELECT 1
SELECT * FROM #Fibonacci
GO

INSERT INTO #Fibonacci(value) 
SELECT SUM(value) FROM ( SELECT TOP 2 * FROM #Fibonacci ORDER BY value DESC ) AS value
GO 10   --  Loop insert 10 value...

SELECT * FROM #Fibonacci
DROP TABLE #Fibonacci

<强> Result Code