我有两个范围:with_category和simple_search。他们每个人都很好地单独工作,但我无法完全得到我需要的东西。
product.rb
has_many :categorizations, :dependent => :destroy
has_many :categories, :through => :categorizations
scope :with_category, lambda { |category_slug|
return {} if category_slug.blank?
joins(:categorizations => :category).where('categorizations.category_id = ?', Category.find_by_slug(category_slug).id).uniq
}
scope :simple_search, lambda { |query|
return {} if query.blank?
where('"products"."name" ~* ? OR "products"."description" ~* ?', query, query)
}
products_controller.rb
def index
@products = Product.with_category(params[:category])
.simple_search(params[:query])
.paginate(:page => params[:page], :per_page => 10)
end
当我转到localhost:3000/products?category=apple-laptops
时,我想抓住当前类别的所有产品。而不是这个,我的 with_category 范围被忽略,我可以看到所有产品。不知道为什么会这样。
从我的日志中:
Product Load (0.9ms) SELECT "products".* FROM "products" LIMIT 10 OFFSET 0
Category Load (0.7ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 2]]
Category Load (0.8ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 4]]
Category Load (0.7ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 10]]
Category Load (0.8ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 5]]
Category Load (0.7ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 18]]
Category Load (0.7ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 1]]
Category Load (0.8ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 3]]
Category Load (0.7ms) SELECT "categories".* FROM "categories" INNER JOIN "categorizations" ON "categories"."id" = "categorizations"."category_id" WHERE "categorizations"."product_id" = $1 [["product_id", 15]]
答案 0 :(得分:1)
您是否尝试过像这样更改范围?
scope :with_category, lambda { |category_slug|
joins(:categorizations => :category).where('categorizations.category_id = ?', Category.find_by_slug(category_slug).id).uniq unless category_slug.blank?
}
scope :simple_search, lambda { |query|
where('"products"."name" ~* ? OR "products"."description" ~* ?', query, query) unless query.blank?
}