std :: thread未定义的行为

Question

下面的代码是否有可能产生未定义的行为？

unsigned int total_threads = 10;
vector<thread> t(total_threads);
unsigned int *nums = (unsigned int*)calloc(total_threads, sizeof(int));

for(unsigned int i = 0; i < 1000; i++)
{
    for(unsigned int j = 0; j < total_threads; j++)
        t[j] = thread(func_, std::ref(nums[j]));

    for(unsigned int j = 0; j < total_threads; j++)
        t[j].join();

    for(unsigned int j = 0; j < total_threads; j++)
    {
        cout << nums[j] << " ";
        nums[j] = 0;
    }
}

Answer 1

是的，因为calloc可能会失败。检查返回值或使用std :: vector。