Question

一般来说，它非常适合Android和编程。

只是想知道是否有人可以帮我在EditText中接受一个单词，然后混淆字母并显示它们？

我尝试了很多不同的事情，这个问题有些帮助How to jumble a word from EditText and apply the jumbled word into a TextView，但我仍然会收到强制关闭错误。

这是我的xml：

<TextView
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:id="@+id/jumble" 
    />

<Button
    android:id="@+id/button"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignLeft="@+id/Editbox1"
    android:layout_below="@+id/Editbox1"
    android:layout_marginTop="18dp"
    android:text="@string/edit_text" />

<EditText
    android:id="@+id/Editbox1"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:layout_marginTop="21dp"
    android:ems="10"
    android:inputType="text"
    android:text="@string/enter_text" >
    </EditText>

和java：

package org.me.myandroidstuff;

import java.util.ArrayList;
import java.util.Collections;

import android.os.Bundle;
import android.app.Activity;
import android.graphics.Typeface;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;
import android.widget.EditText;

public class JumbleTextApplicationActivity extends Activity 
  implements OnClickListener {

  public View TextView;
  public View EditText;
  public View Button;
  EditText editbox = (EditText)findViewById(R.id.Editbox1); 
  TextView jumbledword = (TextView) findViewById(R.id.jumble);
  Button btnJumble = (Button)findViewById( R.id.button );

  @Override
  protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_jumble_text_application);
    TextView tbox1 =(TextView)findViewById(R.id.textBox1);
    tbox1.setTypeface(Typeface.SANS_SERIF);
    tbox1.setTypeface(Typeface.MONOSPACE);
  }

  @Override
  public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.jumble_text_application, menu);
    return true;
  }

  @Override
  public void onClick(View v) {
    btnJumble.setOnClickListener( new View.OnClickListener(){
      public void onClick(View v){
        jumbleMe(editbox.getText().toString());
      }
    });
  }

  private void jumbleMe(String word) {
    ArrayList<Character> jumblew = new ArrayList<Character>();
    for (int i = 0; i < word.length(); i++) {
      jumblew.add(word.charAt(i));
    }
    Collections.shuffle(jumblew);
    String result = "";
    for (Character character : jumblew) {
      result += character;
    }
    jumbledword.setText(result);
  }
}

Answer 1

这个问题正是你所需要的。只需为代码更改

即可

word = (EditText)findViewById(R.id.entry); 
jumble = (TextView) findViewById(R.id.jumble);
Button btnJumble = (Button)findViewById( R.id.button );

btnJumble.setOnClickListener( new View.OnClickListener(){
    public void onClick(View v){
        jumbleMe(word.getText().toString());
}

How to jumble a word from EditText and apply the jumbled word into a TextView

修改

试试这个

<TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/jumble"/> <Button android:id="@+id/button" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignLeft="@+id/Editbox1" android:layout_below="@+id/Editbox1" android:layout_marginTop="18dp" android:text="@string/edit_text" /> <EditText android:id="@+id/Editbox1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_marginTop="21dp" android:ems="10" android:inputType="text" android:text="@string/enter_text" />

和java：

package org.me.myandroidstuff; import java.util.ArrayList; import java.util.Collections; import android.os.Bundle; import android.app.Activity; import android.graphics.Typeface; import android.view.Menu; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.TextView; import android.widget.EditText; public class JumbleTextApplicationActivity extends Activity{ public View TextView; public View EditText; public View Button; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_jumble_text_application); EditText editbox = (EditText)findViewById(R.id.Editbox1); TextView jumbledword = (TextView) findViewById(R.id.jumble); Button btnJumble = (Button)findViewById( R.id.button ); TextView tbox1 =(TextView)findViewById(R.id.textBox1); tbox1.setTypeface(Typeface.SANS_SERIF); tbox1.setTypeface(Typeface.MONOSPACE); btnJumble.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { jumbleMe(editbox.getText().toString()); } }); } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.jumble_text_application, menu); return true; } private void jumbleMe(String word) { ArrayList<Character> jumblew = new ArrayList<Character>(); for (int i = 0; i < word.length(); i++) { jumblew.add(word.charAt(i)); } Collections.shuffle(jumblew); String result = ""; for (Character character : jumblew) { result += character; } jumbledword.setText(result); } }

Answer 2

String text = yourTextView.getText().toString();
String[] words = text.split("\\s+");
List<String> wordList = Arrays.asList(words);
Collections.shuffle(wordList);
text = StringUtils.join(wordList, " ");
yourTextView.setText(text);

在点击监听器上的按钮内执行此操作以随机播放单词。对于forceclose提供logcat

通过单击按钮从EditText中发出混乱的字母

2 个答案: