Question

我已成功从Bing's-Search-API中的Java下载图片。但是，我不明白如何处理回复。

例如，如果找不到图片，或者用户试图搜索成人内容（即使设置为中等），我应该如何catch这些回复？

非常感谢。

这是我的代码：

public void SearchWithBing(String search){

        search = search.replaceAll(" ", "%20");
        String accountKey="acKey";
        byte[] accountKeyBytes = Base64.encodeBase64((accountKey + ":" + accountKey).getBytes());
        String accountKeyEnc = new String(accountKeyBytes);
        URL url;
        try {
            url = new URL(
                    "https://api.datamarket.azure.com/Bing/Search/Image?Query=%27" + search + "%27&$top=50&$format=json");

        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setRequestMethod("GET");
        conn.setRequestProperty("Authorization", "Basic " + accountKeyEnc);
        conn.setRequestProperty("Accept", "application/json");
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));
        String output;
        System.out.println("Output from Server .... \n");

        while ((output = br.readLine()) != null) {
                gsonParser(output);
                System.out.println(output);
        }

        conn.disconnect();

        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

       //EndOfBingSearch  
    }

Answer 1

你可以使用Gson：

    Gson gson = (new GsonBuilder()).create();
BingSearchResults bingSearchResults = gson.fromJson(res, BingSearchResults.class);

使用以下课程：

public class BingSearchResults {

public ResultsContent d;

public static class ResultsContent {
    public Result[] results;
    public String __next;
}

public static class Result {
    public String ID;
    public String Title;
    public String Description;
    public String DisplayUrl;
    public String Url;
    public Metadata __metadata;

}

public static class Metadata {
    public String uri;
    public String type;
}

}

如何正确处理Java中Bing Search API的响应？

1 个答案: