我正在尝试解析下面的json对象,但我不知道如何做到这一点因为json对象中的“讲师”?我不知道如何管理“讲师”他们是Json中的另一个对象但是在数据[0]中它是一个对象和数据[1]它是一个标志或布尔值。这件事让我很困惑。任何想法我怎么能实现这个???
{
"result": "Success",
"data": [
{
"student_course_id": "82",
"student_id": "30",
"term_course_id": "18",
"section_id": "3",
"term_id": "12",
"course_id": "15",
"credit_hours": "26",
"is_elective": "Elective",
"is_practical": "0",
"teacher_id": "10",
"program_id": "5",
"course_code": "E2",
"course_title": "English 2",
"lecturer": {
"fname": "Ali",
"lname": "farooq",
"phone": "1234567890",
"email": "farooq@teacher.com",
"thumb": "../photos/thumb/1391515491.png"
}
},
{
"student_course_id": "83",
"student_id": "30",
"term_course_id": "19",
"section_id": "3",
"term_id": "12",
"course_id": "16",
"credit_hours": "26",
"is_elective": "Elective",
"is_practical": "0",
"teacher_id": "8",
"program_id": "5",
"course_code": "C2",
"course_title": "Culture 2",
"lecturer": false
}
]
}
C#代码
public async static Task<StudentSubjectsClassWithError> StudentSubjectsList()
{
HttpClient client = new HttpClient();
string baseUrl = getBaseUrl();
try
{
string flickrResult = await client.GetStringAsync(baseUrl);
StudentSubjectsClassWithError studentSubjectsResult = new StudentSubjectsClassWithError();
try
{
StudentSubjectsJson apiData =
JsonConvert.DeserializeObject<StudentSubjectsJson>(flickrResult);
List<StudentSubjectsClass> mStudentSubjectsList = new List<StudentSubjectsClass>();
if (apiData.data != null && apiData.result == "Success")
{
studentSubjectsResult.message = "";
studentSubjectsResult.result = apiData.result;
foreach (StudentSubjectsJsonItem data in apiData.data)
{
StudentSubjectsClass studentSubjects = new StudentSubjectsClass();
studentSubjects.student_course_id = data.student_course_id;
studentSubjects.student_id = data.student_id;
studentSubjects.term_course_id = data.term_course_id;
studentSubjects.section_id = data.section_id;
studentSubjects.term_id = data.term_id;
studentSubjects.course_id = data.course_id;
studentSubjects.credit_hours = data.credit_hours;
studentSubjects.is_elective = data.is_elective;
studentSubjects.is_practical = data.is_practical;
studentSubjects.program_id = data.program_id;
studentSubjects.course_code = data.course_code;
studentSubjects.course_title = data.course_title;
//// studentSubjects.lecturer ?????
mStudentSubjectsList.Add(studentSubjects);
}
}
else
{
studentSubjectsResult.result = apiData.result;
studentSubjectsResult.message = "No records found.";
}
studentSubjectsResult.studentSubjectsList = mStudentSubjectsList;
return studentSubjectsResult;
}
catch (JsonSerializationException)
{
try
{
StudentSubjectsErrorJson apiData =
JsonConvert.DeserializeObject<StudentSubjectsErrorJson>(flickrResult);
studentSubjectsResult.result = apiData.result;
studentSubjectsResult.message = apiData.data;
studentSubjectsResult.studentSubjectsList = null;
return studentSubjectsResult;
}
catch (JsonSerializationException)
{
}
}
return null;
}
catch (Exception)
{
return null;
// MessageBox.Show("Internet Connection Problem");
}
}
答案 0 :(得分:5)
我正在使用Visual Studio 2012,当我想将Json字符串转换为C#类对象时,我复制了Json字符串并且
-> Click Edit
-> Click Paste Special
-> Click Paste JSON as Classes
或者您可以使用Jonathan Keith http://json2csharp.com/
提供的精彩在线工具使用json2csharp我从你的json
获得了这个类public class Datum
{
public string student_course_id { get; set; }
public string student_id { get; set; }
public string term_course_id { get; set; }
public string section_id { get; set; }
public string term_id { get; set; }
public string course_id { get; set; }
public string credit_hours { get; set; }
public string is_elective { get; set; }
public string is_practical { get; set; }
public string teacher_id { get; set; }
public string program_id { get; set; }
public string course_code { get; set; }
public string course_title { get; set; }
public object lecturer { get; set; }
}
public class RootObject
{
public string result { get; set; }
public List<Datum> data { get; set; }
}
修改强>
我还注意到你的数据数组有讲师作为对象,第二个数据有讲师作为bool。如果它不存在,你可以通过简单地不包括讲师来解决这个问题。这会将类更改为:
public class Lecturer
{
public string fname { get; set; }
public string lname { get; set; }
public string phone { get; set; }
public string email { get; set; }
public string thumb { get; set; }
}
public class Datum
{
public string student_course_id { get; set; }
public string student_id { get; set; }
public string term_course_id { get; set; }
public string section_id { get; set; }
public string term_id { get; set; }
public string course_id { get; set; }
public string credit_hours { get; set; }
public string is_elective { get; set; }
public string is_practical { get; set; }
public string teacher_id { get; set; }
public string program_id { get; set; }
public string course_code { get; set; }
public string course_title { get; set; }
public Lecturer lecturer { get; set; }
}
public class RootObject
{
public string result { get; set; }
public List<Datum> data { get; set; }
}
答案 1 :(得分:0)
您获得了最高级别StudentSubjectsJson
,StudentSubjectsJsonItem
数组中每个等级获得data
。
对于讲师,您需要定义StudentSubjectsJsonLecturer
并设置为StudentSubjectsJsonItem
lecturer
的属性。
例如:
public class StudentSubjectsJsonItem {
//Existing properties
public StudentSubjectsJsonLecturer lecturer {get;set;}
}
public class StudentSubjectsJsonLecturer {
public string fname {get;set;}
public string lname {get;set;}
//And so on...
}
答案 2 :(得分:0)
由于您已经在复制属性(您不应该这样做,这就是反序列化的用途),您可以将数据反序列化为dynamic
对象(Newtonsoft Json v4 +):
dynamic apiData = JsonConvert.DeserializeObject<StudentSubjectsJson>(flickrResult);
然后继续执行其余代码,然后当你必须处理`讲师'时,检查它是否像往常一样“假”:
if (apiData.data[x].lecturer != false){
...
}
免责声明:我没有对此进行编译尝试,这是一个建议尝试的内容
答案 3 :(得分:0)
我建议您使用第三方json库而不是自己编写一个。特别是这一个:click to download
它是一个单文件的json库。