Question

以下查询返回结果：

  SELECT id_a, 
         id_b, 
         id_c
    FROM (
         SELECT id_a, 
                id_b, 
                id_c, 
                Dep_Travail_b
           FROM (
                SELECT A.ID id_a, 
                       B.ID id_b, 
                       B.Dep_Travail Dep_Travail_b
                  FROM [regal-cider-369:insee_recensement_1968_2010.Dep_Naissance] A 
                       INNER JOIN [regal-cider-369:insee_recnsement_1968_2010.Dep_Travail] B 
                                  ON A.ID = B.ID
                ) as JOIN1
                           INNER JOIN (
                                       SELECT ID id_c 
                                         FROM [regal-cider-369:insee_recnsement_1968_2010.Dep_Residence] C
                                      ) as C
                                      ON id_a = id_c
         )
ORDER BY id_a, 
         id_b, 
         id_c

但如果ORDER BY子句被GROUP BY替换，则返回以下错误：

找不到字段'id_c';你是说'id_a'吗？

相同查询的简化版本导致相同的结果（在查询结束时使用ORDER BY，使用GROUP BY失败）。

  SELECT id_a, 
         id_b, 
         id_c
    FROM (
          SELECT A.ID id_a ,
                 B.ID id_b
            FROM [regal-cider-369:insee_recensement_1968_2010.Dep_Naissance] A 
                 INNER JOIN [regal-cider-369:insee_recensement_1968_2010.Dep_Travail] B 
                            ON A.ID = B.ID
         ) as JOIN1
                   INNER JOIN (
                               SELECT ID id_c 
                                 FROM [regal-cider-369:insee_recensement_1968_2010.Dep_Residence] C
                               ) as C
                              ON id_a = id_c
ORDER BY id_a, 
         id_b, 
         id_c

GROUP BY和加入是否有问题，或者我错过了什么？

Answer 1

当我为所选字段添加别名（字段，字段，字段）时，它似乎正在工作，与GROUP BY一起使用的简单版本是：

    SELECT id_a AS fieldA, 
           id_b as fieldB, 
           id_c as fieldC
    FROM (
          SELECT A.ID id_a ,
                 B.ID id_b
            FROM [regal-cider-369:insee_recensement_1968_2010.Dep_Naissance] A 
                 INNER JOIN [regal-cider-369:insee_recensement_1968_2010.Dep_Travail] B 
                            ON A.ID = B.ID
         ) as JOIN1
                   INNER JOIN (
                               SELECT ID id_c 
                                 FROM [regal-cider-369:insee_recensement_1968_2010.Dep_Residence] C
                               ) as C
                              ON id_a = id_c
GROUP BY fieldA, 
         fieldB, 
         fieldC

BigQuery 3表按问题加入+ group

1 个答案: