Question

我正在尝试通过javascript制作谷歌缩短分析工具，这是我的代码：

 <script>

  function makeRequest() {
    for (var i=0; i < shortUrl.length; i++){
      var url = shortUrl[i];
      var request = gapi.client.urlshortener.url.get({
        'shortUrl': url,
        'projection':'FULL',
      });
      request.execute(function(response) {
        console.log(response); //here is the problem begin
        var result = {
          short: response.id,
          clicks: response.analytics.allTime.shortUrlClicks
        };
        appendResults(result, i);         
      });
    }
  }

  function load() {
    gapi.client.setApiKey('xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx');
    gapi.client.load('urlshortener', 'v1', makeRequest);
  }
</script>
<script src="https://apis.google.com/js/client.js?onload=load"></script>

每次结果都会让我与众不同！例如： SHORTURL [1,2,3,4] 它将返回3,2,1,4或1,2,4,3 ......等等。

我的代码出了什么问题？是异步问题？我该怎么办呢？请帮我！ THX

Answer 1

因为ajax是异步的。你必须使用承诺。 jQuery示例。

var promises = [];
for (var i=0; i < shortUrl.length; i++){

  var dfd = new $.Deferred;

  var url = shortUrl[i];
  var request = gapi.client.urlshortener.url.get({
    'shortUrl': url,
    'projection':'FULL',
  });
  request.execute((function(dfd){return function(response) {
    dfd.resolve(response);      
  };})(dfd));

  promises.push(dfd.promise());
}

$.when.apply($, promises).done(function(){
  promises = undefined;
  for(var i in arguments){
    var response = arguments[i];
    console.log(response); //here is the problem begin
    var result = {
      short: response.id,
      clicks: response.analytics.allTime.shortUrlClicks
    };
    appendResults(result, i);  
  }
});

我的工作代码：

var promises = [];

var request = function(i, callback){
setTimeout(function(){return callback(i);},100 - i);  
}

for (var i=0; i < 10; i++){

  var dfd = new $.Deferred;

  request(i, (function(dfd){return function(response) {
    dfd.resolve(response);      
  };})(dfd));

  promises.push(dfd.promise());
}

$.when.apply($, promises).done(function(){
  promises = undefined;
  for(var i in arguments){

    console.log(arguments[i]); 

  }
});

为什么我的jquery .get（）结果无法通过我给出的顺序显示

1 个答案: