Question

我差不多2年前发布了以下问题并得到了一个完美的答案，但现在我需要扩展这个问题以获得缺货持续时间。这是我提供的原始问题和答案：

＆＃34;我需要确定库存库存和缺货的模式。

我有一张表格，显示项目，位置，库存和日期。我想知道一个项目/位置缺货的情况是否存在时间模式。该文件包含滚动三周的数据。如果一件物品在三周内持续不稳定或缺货，那么我需要了解它以进一步研究。

如果库存大于零，则项目/位置是instock。如果库存为零或为负，则物料/库位缺货。

感谢您的帮助。

示例数据

Item, location, inventory, date
1243, 10,       2,         3/12/2012
1243, 10,       0,         3/13/2012
1243, 10,      -2,         3/14/2012
1243, 10,      -2,         3/15/2012
1243, 10,       4,         3/16/2012

然后添加项目，位置，库存，日期记录。＆＃34;

我收到了这个答案，效果很好。

SELECT item,
   location,
   SUM( CASE WHEN status = 'In Stock' AND prior_status = 'Out of Stock'
             THEN 1
             ELSE 0
         END) moved_to_out_of_stock,
   SUM( CASE WHEN status = 'Out of Stock' AND prior_status = 'In Stock'
             THEN 1
             ELSE 0 
          END) moved_to_in_stock
  FROM (SELECT item, 
           location,
           status,
           lag( status ) over (partition by item, location
                                   order by dt) prior_status
      FROM (SELECT item, 
                   location, 
                   (case when inventory <= 0 
                         then 'Out of Stock'
                         else 'In Stock'
                     end) status,
                   dt
              FROM your_table))
  GROUP BY item, location

现在我希望能够确定“缺货”的持续时间。每次发生。基本上这个项目有多少天，每次缺货时都会缺货。

非常感谢任何帮助。

EDIT 这是我目前使用的查询：

select ari.ITEM, x.LOCATION, MOVED_TO_OUT_OF_STOCK, MOVED_TO_IN_STOCK
from (select item, location, 
SUM(CASE WHEN status = 'In Stock' AND prior_status = 'Out of Stock'
                THEN 1
                ELSE 0
             END)
moved_to_out_of_stock,
SUM(CASE WHEN status = 'Out of Stock' AND prior_status = 'In Stock'
                THEN 1
                ELSE 0
             END)
moved_to_in_stock
  FROM (select item, location, status, lag(status)
  over (partition by item, location
  order by repl_date) prior_status
  FROM (select item, location,(CASE WHEN (stock_on_hand - demo_stock - non_sellable_qty) <='0'--subtract demo stock and non sellable qty
  then 'Out of Stock'
  else 'In Stock'
  end)
  status, repl_date
  from repl_results))
  group by item, location) x, active_repl_items ari,
  (select item, location, min(repl_date) as min_repl_date from repl_results
  group by item, location)y,
  (select item, location, repl_date, (STOCK_ON_HAND-DEMO_STOCK-NON_SELLABLE_QTY) AS  NET_AVAIL from repl_results) z
where (x.item = ari.item or x.item = ari.primary_pack_no) --to account for pack_items
and x.item = y.item and x.item = z.item
and x.location = y.location and x.location = z.location
and y.min_repl_date = z.repl_date
and x.location = ari.location

Answer 1

以下是解决问题的方法。每次发现缺货情况时添加0/1标志。然后做这个标志的累积总和。该累计金额按顺序识别缺货情况。当您按此累计金额汇总时，您可以获得缺货情况的持续时间：

select item, location, ooi_grp, min(dt) as mindt, max(dt) as maxdt,
       (max(dt) - min(dt) + 1) as duration
from (select t.*, sum(startooi_flag) over (partition by item, location order by dt) as ooi_grp
      FROM (SELECT item, location, status,
                   (case when lag(inventory) over (partition by item, location order by dt) > 0 and
                              inventory <= 0
                         then 1 else 0
                    end) as startooi_flag
            FROM your_table
           ) t
     ) t
where inventory <= 0
group by item, location;

库存缺货持续时间

1 个答案: