我有一张像
这样的表格**ID Value1 Value2**
11 AAAA ZZZZ
11 A134 ZZZZ
12 BBBB YYYY
12 B222 YYYY
13 CCCC XXXX
13 A134 XXXX
我需要结果如下
ID Value1 Value2
11 AAAA ZZZZ
12 BBBB YYYY
13 CCCC XXXX
请帮我解决这个问题。
答案 0 :(得分:1)
;with cte as
(
select id,value1,value2,row_number() over(partition by id order by id) as rn from #t
)
select id,value1,value2 from cte where rn=1
答案 1 :(得分:0)
我们也可以这样做以获得所需的输出
Select * FROM (
select id,value1,value2,ROW_NUMBER()OVER (PARTITION BY ID ORDER BY Value1)AS RN from #t
)t
WHERE RN = 1
oR
Select t.ID,t.value1,t.value2 FROM #t t
INNER JOIN (Select DISTINCT ID,value1,value2 FROM #t GROUP BY id,value1,value2)tt
ON tt.id = t.id AND tt.value1 = t.value1 AND tt.value2 = t.value2
ORDER BY t.value1 ASC,t.value2 ASC