我正在玩LDAP和Java搜索。 这是我的LDIF导出,具有简单的组织
version: 1
dn: dc=example,dc=com
objectClass: organization
objectClass: dcObject
objectClass: top
dc: example
o: MyOrganization
description: Test Description
dn: ou=people, dc=example,dc=com
objectClass: organizationalUnit
objectClass: top
ou: people
description: All users in demo company
dn: cn=Johnny Doe,ou=people,dc=example,dc=com
objectClass: organizationalPerson
objectClass: person
objectClass: inetOrgPerson
objectClass: top
cn: Johnny Doe
sn: Johnny
homephone: 123-456-7890
mail: johnny@johnny.com
ou: Development
uid: jjohnny
userpassword:: johnny
dn: cn=Samuel Johnson,ou=people,dc=example,dc=com
objectClass: organizationalPerson
objectClass: person
objectClass: inetOrgPerson
objectClass: top
cn: Samuel Johnson
sn: Samuel
homephone: 123-456-7890
mail: sam@ssam.com
ou: Accounts
uid: ssam
userpassword:: sammy
如何运行Java代码段以从LDAP服务器获取所有用户?我的Apache DS Directory Server上没有设置身份验证。
Hashtable env = new Hashtable(11);
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://localhost:10389/dc=example,dc=com");
env.put(Context.SECURITY_AUTHENTICATION, "none");
try {
// Create initial context
DirContext ctx = new InitialDirContext(env);
Object obj = new Object();
// want to print all users from the LDAP server
System.out.println(obj.toString());
ctx.close();
}
答案 0 :(得分:46)
另一种方法是使用UnboundID。它的api非常易读且更短
创建Ldap连接
public static LDAPConnection getConnection() throws LDAPException {
// host, port, username and password
return new LDAPConnection("com.example.local", 389, "Administrator@com.example.local", "admin");
}
获取过滤结果
public static List<SearchResultEntry> getResults(LDAPConnection connection, String baseDN, String filter) throws LDAPSearchException {
SearchResult searchResult;
if (connection.isConnected()) {
searchResult = connection.search(baseDN, SearchScope.ONE, filter);
return searchResult.getSearchEntries();
}
return null;
}
获取所有Oragnization单位和容器
String baseDN = "DC=com,DC=example,DC=local";
String filter = "(&(|(objectClass=organizationalUnit)(objectClass=container)))";
LDAPConnection connection = getConnection();
List<SearchResultEntry> results = getResults(connection, baseDN, filter);
获取特定的组织单位
String baseDN = "DC=com,DC=example,DC=local";
String dn = "CN=Users,DC=com,DC=example,DC=local";
String filterFormat = "(&(|(objectClass=organizationalUnit)(objectClass=container))(distinguishedName=%s))";
String filter = String.format(filterFormat, dn);
LDAPConnection connection = getConnection();
List<SearchResultEntry> results = getResults(connection, baseDN, filter);
获取组织单位下的所有用户
String baseDN = "CN=Users,DC=com,DC=example,DC=local";
String filter = "(&(objectClass=user)(!(objectCategory=computer)))";
LDAPConnection connection = getConnection();
List<SearchResultEntry> results = getResults(connection, baseDN, filter);
获取组织单位下的特定用户
String baseDN = "CN=Users,DC=com,DC=example,DC=local";
String userDN = "CN=abc,CN=Users,DC=com,DC=example,DC=local";
String filterFormat = "(&(objectClass=user)(distinguishedName=%s))";
String filter = String.format(filterFormat, userDN);
LDAPConnection connection = getConnection();
List<SearchResultEntry> results = getResults(connection, baseDN, filter);
显示结果
for (SearchResultEntry e : results) {
System.out.println("name: " + e.getAttributeValue("name"));
}
答案 1 :(得分:45)
try {
LdapContext ctx = new InitialLdapContext(env, null);
ctx.setRequestControls(null);
NamingEnumeration<?> namingEnum = ctx.search("ou=people,dc=example,dc=com", "(objectclass=user)", getSimpleSearchControls());
while (namingEnum.hasMore ()) {
SearchResult result = (SearchResult) namingEnum.next ();
Attributes attrs = result.getAttributes ();
System.out.println(attrs.get("cn"));
}
namingEnum.close();
} catch (Exception e) {
e.printStackTrace();
}
private SearchControls getSimpleSearchControls() {
SearchControls searchControls = new SearchControls();
searchControls.setSearchScope(SearchControls.SUBTREE_SCOPE);
searchControls.setTimeLimit(30000);
//String[] attrIDs = {"objectGUID"};
//searchControls.setReturningAttributes(attrIDs);
return searchControls;
}
答案 2 :(得分:6)
您还可以使用以下代码:
package com.agileinfotech.bsviewer.ldap;
import java.util.Hashtable;
import java.util.ResourceBundle;
import javax.naming.Context;
import javax.naming.NamingException;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
public class LDAPLoginAuthentication {
public LDAPLoginAuthentication() {
// TODO Auto-generated constructor
}
ResourceBundle resBundle = ResourceBundle.getBundle("settings");
@SuppressWarnings("unchecked")
public String authenticateUser(String username, String password) {
String strUrl = "success";
Hashtable env = new Hashtable(11);
boolean b = false;
String Securityprinciple = "cn=" + username + "," + resBundle.getString("UserSearch");
env.put(Context.INITIAL_CONTEXT_FACTORY, resBundle.getString("InitialContextFactory"));
env.put(Context.PROVIDER_URL, resBundle.getString("Provider_url"));
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, Securityprinciple);
env.put(Context.SECURITY_CREDENTIALS, password);
try {
// Create initial context
DirContext ctx = new InitialDirContext(env);
// Close the context when we're done
b = true;
ctx.close();
} catch (NamingException e) {
b = false;
} finally {
if (b) {
strUrl = "success";
} else {
strUrl = "failer";
}
}
return strUrl;
}
}