Question

在下面的多维数组中，我想合并具有相同merge_id的数组。我不确定“merge”是否是正确的单词：在下面的示例中，数组['0']应该成为数组['0']，其中包含数组['0'] ['0']和数组[' 0'] ['1']，后者等于数组['1']。我希望这是有道理的......

数组来自在merge_id上排序的数据库，因此具有匹配merge_id的数组总是彼此“相邻”，并且只有2具有相同的merge_id

当我循环遍历数组时，我知道我需要保留一个始终等于前一个merge_id的变量，如果前一个和当前之间存在匹配，则合并。

Array
(
    [0] => Array
        (
            [client_id] => 5
            [company_name] => company111_name
            [id] => 3
            [fee] => 111
            [year] => 2009
            [quarter] => 3
            [date_inserted] => 1264948583
            [description] => 2009 - Q3


            [fee_type] => 
            [merge_id] => a87ff679a2f3e71d9181a67b7542122c
            [total_paid] => 0
            [total_remainder] => 0
        )

    [1] => Array
        (
            [client_id] => 5
            [company_name] => company111_name
            [id] => 6
            [fee] => 55.5
            [year] => 2010
            [quarter] => 2
            [date_inserted] => 1264949470
            [description] => 2010 - Q2


            [fee_type] => 
            [merge_id] => a87ff679a2f3e71d9181a67b7542122c
            [total_paid] => 0
            [total_remainder] => 0
        )

    [2] => Array
        (
            [client_id] => 5
            [company_name] => company111_name
            [id] => 4
            [fee] => 111
            [year] => 2009
            [quarter] => 4
            [date_inserted] => 1264948583
            [description] => 2009 - Q4


            [fee_type] => 
            [merge_id] => 
            [total_paid] => 0
            [total_remainder] => 0
        )



    [3] => Array
        (
            [client_id] => 5
            [company_name] => company111_name
            [id] => 7
            [fee] => 55.5
            [year] => 2010
            [quarter] => 3
            [date_inserted] => 1264949470
            [description] => 2010 - Q3


            [fee_type] => 
            [merge_id] => 
            [total_paid] => 0
            [total_remainder] => 0
        )

)

代码

$merger = $data['search']['0']['merge_id'];
            $i = 0;
            foreach($data['search'] as $fee)
            {
                if($fee['merge_id'] == $merger)
                {
                    //bump up & merge arrays
                    ???
                }           

                $merger = $fee['merge_id'];
                $i++;
            }

Answer 1

您可以使用ID作为键将所有具有相同ID的项目放在同一个数组中：

$merged = array();
foreach ($data['search'] as $fee) {
    if ($fee['merge_id'] == '') {
        continue;
    }
    if (!isset($merged[$fee['merge_id']])) {
        $merged[$fee['merge_id']] = array();
    }
    $merged[$fee['merge_id']][] = $fee;
}
$merged = array_values($merged);

请注意，这将跳过具有空合并ID的项目。在这种情况下，您也可以使用continue;替换$fee['merge_id'] = 0;来使用默认合并ID。

Answer 2

  foreach($array as $p)
      $result[$p['merge_id']][] = $p;

php合并数组

2 个答案: