Question

Sonar为以下代码提供了严重违规错误（“保留堆栈跟踪”）。以下方法用于抛出异常。我应该采取什么措施来克服这种违规行为？

public void exceptionHandler(String exception) throws PhDashException {

    String exceptionMsg = exception.replaceAll("-", "_");

    ExceptionPhDash pHDashExceptionMapper = new ExceptionPhDash();
    try {
        pHDashExceptionMapper = new ObjectMapper().readValue(exceptionMsg, ExceptionPhDash.class);
    } catch (JsonParseException e) {
        LOGGER.info(e.getMessage());
    } catch (JsonMappingException e) {
        LOGGER.info(e.getMessage());
    } catch (IOException e) {
        LOGGER.info(e.getMessage());
    }
    throw new PhDashException(pHDashExceptionMapper.getMessage());
}

Answer 1

您已记录每个例外;就保存信息而言，这应该足够了，如下所示，

LOGGER.info("Unexpected Exception has occurred", e);

或者如果可以，你应该抛出PhDashException因为，就保存信息而言，你应该足够了

throw new PhDashException(pHDashExceptionMapper);

如何避免Sonar的“保留堆栈跟踪”违规？

1 个答案: