Question

我有一个这样的字符串： 2,100|7,104|15,1110

我如何转换它以便在每个|之前获得第一个值的数组？

Array
(
    [2] => 100
    [7] => 104
    [15] => 1100
)

Answer 1

这是一种做法

$str = '2,100|7,104|15,1110';

$arr1 = explode("|",$str);

if(sizeof($arr1) > 0 ){
    $final_array = array() ;
    foreach($arr1 as $data){
            $arr2 = explode(",",$data);
            $final_array[$arr2[0]] = $arr2[1];
    }
}

print_r($final_array);

Answer 2

您可以使用array_walk和explode来执行此操作。

$array = array();
$string = "2,100|7,104|15,1110";

array_walk(explode("|", $string), function($value) use(&$array) {
    $group = explode(",", $value);
    $array[$group[0]] = $group[1];
});

PHP 5.4 +

Answer 3

使用explode

<?php

$pipeString = "2,100|7,104|15,1110";
$exploded = explode("|", $pipeString);
$outputArray = array();

for($i = 0, $l = count($exploded); $i < $l; $i++){
  $keyValues = explode(",", $exploded[$i]);

  $outputArray[$keyValues[0]] = $keyValues[1];
}

var_dump($outputArray);
?>

Answer 4

你在问题上有一个错字，所以我做一个假设。你可以这样做。

    $str = "2,100|7,104|15,1100";
    foreach (explode("|", $str) as $part) {
        $parts = explode(",", $part); 
        $my_array[$parts[0]] = $parts[1];
    }

Answer 5

像Yatin Trivedi所说，爆炸两次应该会给你你想要的结果：

$string  = '2,100|7,104|15,1110';
$result = array();
foreach (explode('|', $string) as $entry) {
  $values = explode(',', $entry);
  $result[$values[0]] = $values[1];
}

Answer 6

<?php

function explodeThem($string) {
    $explode0= explode("|", $string);

    for ($i=0; $i<count($explode0); $i++) {
        $explode1 = explode(",", $explode0[$i]);
        $newArray[$explode1[0]] = $explode1[1];
    }

    return $newArray;
}

$string = "2,100|7,104|15,1110";
echo "<pre>";
var_dump(explodeThem($string));
echo "</ pre>";

将字符串转换为数组

6 个答案: